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- Which is most basic leaving group among the listed below? a. –O–CO–R b. –NH2 c. –O–R d. Cl–2. How many substitution product/s is/are formed when metabromo anisole is treated with ammonia?A. 0-no reactionB. 1C. 2D. 3Drawing the SN1 and E1 Products in a ReactionDraw the SN1 and E1 products formed in the reaction of (CH3)3CBr with H2O.
- Which of the following chemical equations depicts an alkylation reaction? C6H6() + CH3Cl() → C6H5CH3() + HCl(g) 2 CH3OH() + 3 O2(g) → 2 CO2(g) + 4 H2O() C6H12() → C6H10() + H2(g) CH2ClCH2Cl(g) + H2(g) → CH3CH3(g) + Cl2(g) CHClCHCl(g) → CH2ClCH2Cl(g)Circle the electrophiles in the following reagents: AlCl3 NO3– NO2+ H3O+ OH-The answer choices for part b ["How would you convert the alkene to a epoxide?"] are: (a) Br2/NaNH2 in liq NH3; (b) mCPBA; (c) OsO4Thank you!
- Draw the mechanism ffrom benzaldehyde to this using: i)NaBH4 ii)TsCl, py iii)NaCN iiii)H+, H2OWhat is the rate law implied by the mechanism given below? CH3COCH3(aq) + H+(aq) ←→ CH3C(OH)CH3+(aq) (fast, reversible) CH3C(OH)CH3+(aq) → CH3C(OH)=CH2(aq) + H+(aq) (slow) CH3C(OH)=CH2(aq) + Br2(aq) → CH3C(OH)CH2Br+(aq) + Br-(aq) (fast) CH3C(OH)CH2Br+(aq) → CH3COCH2Br(aq) + H+(aq) (fast) A. Rate = k[CH3COCH3][H+] B. Rate = k[CH3COCH3] C. Rate = k[CH3COCH3][Br2] D. Rate = k[CH3COCH3]2 E. Rate = k[CH3COCH3][Br2]/[H+] (Answer is A, looking for explanation why!).What alkenes are formed from each alkyl halide by an E2 reaction? Use the Zaitsev rule to predict the major product.
- Tertiary alkyl halides will react by E2 under neutral conditions under acidic conditions under basic conditions will not react by E2What alkene is the major product formed from each alkyl halide in an E1 reaction?Rank the species in each group in order of increasing nucleophilicity. a. CH3CH2S−CH3CH2O−, CH3CO2− in CH3OH b. CH3NH2, CH3SH, CHOH in acetone c.−OH, F−, Cl− in acetone d. HS−, F−, Cl− in CH3OH
