Which of the following is FALSE about interpreting the results of normal microbial flora experiment? 1. Blood plates demonstrate the presence of pathogenic Beta Hemolytic Strep 2. There may be Staph specie, fungus and Strep species present 3. The presence of S. aureus could mean you are carrying MRSA 4.Plates with no growth means the individual is very healthy 5.No growth on Sabouraud agar means you are not carrying any yeast on your

Which of the following is FALSE about interpreting the results of normal microbial flora experiment? 1. Blood plates demonstrate the presence of pathogenic Beta Hemolytic Strep 2. There may be Staph specie, fungus and Strep species present 3. The presence of S. aureus could mean you are carrying MRSA 4.Plates with no growth means the individual is very healthy 5.No growth on Sabouraud agar means you are not carrying any yeast on your

Microbiology for Surgical Technologists (MindTap Course List)

2nd Edition

ISBN:9781111306663

Author:Margaret Rodriguez, Paul Price

Publisher:Margaret Rodriguez, Paul Price

Chapter12: Gram-positive Cocci

Section: Chapter Questions

Problem 4UTM

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Which of the following is FALSE about interpreting the results of normal microbial flora experiment? Question 1 options: A Plates with no growth means the individual is very healthy B No growth on Sabouraud agar means you are not carrying any yeast on your hands C Blood plates demonstrate the presence of pathogenic Beta Hemolytic Strep D The presence of S. aureus could mean you are carrying MRSA E There may be Staph specie, fungus and Strep species present
You are given a 1 gram soil sample of unknown bacterial load. After doing 10-fold serial dilutions of the soil in sterile water, 100 uL volumes are taken from each dilution for preparation of pour plates. Following incubation, each half of the 10-8 plate has 46 colonies.a) What was the dilution factor?b) How many bacteria were present in the soil?2. Staphylococcus aureus divides every 20 minutes. A culture begins with 10 bacterial cells.a) After 5 hours, how many generations have occurredb) After 5 hours, how many bacteria are present?3. How many milliliters would you need to prepare a 10-2 dilution from a 10ml starting culture?
A microbiology student was given a mixed culture of two different gram positive bacteria species to grow into a culture medium using correct aseptic techniques. After two days,one gram positive bacterial species grew on the media and the growth appeared red on the surface of the medium. Tthe second gram positive bacterial species grew and the growth appeared yellow on the surface of the medium. What is the possible explanation for the differences in the color of the bacterial growth? A. the culture was contaminated B. the microbiologist put too much inoculum on the culture medium C. the medium was a selective medium D. the medium was differential
The thermal death point is best described as:(a) The highest temperature that will support growth of amicrobial culture(b) The length of time required for killing 100% of mi-crobes in a 24-hour culture that is heated to 100°C(c) The temperature at which a previously growing 24-hourculture will begin to die(d) The temperature at which 100% of the microbes in a24-hour culture will be killed in 10 minutes
1. Which materials are to be prepared when using Spread Plate technique for bacterial isolation from water sample of oligotrophic Lake Lanao? Check all that apply. ( ) lake water sample ( ) sterile nutrient agar plate ( ) sterilizable glass rod ( ) flame source 2. Which ranges of microbial colony count is ideal standard for a good plate in Pour Plate technique? Check all that apply. ( ) TNTC (too numerous to count) ( ) 25-250 colonies ( ) 10-1000 colonies ( ) 30-300 colonies
Using a dilution series is a way to transfer the very small volumes of original culture necessary to get countable colony forming units. If you suspect your culture of bacteria has 59.62*10^9 cells per mL, how many mL of original culture would you want to end up on the plate to produce 68 cfu? Express your answer in scientific notation rounded to two decimal places. Eg. 0.01001 would be 1.00*10^-2 You must include trailing zeros 0.0000040001 would be reported as 4.00*10^-6 There must always be two decimal places, even if they are zeros Canvas expects one digit before the decimal point 0.40*10^-5 would be marked incorrect for 0.0000040001
You were tasked to aseptically collect different environmental samples from a quarry site and process them back in the laboratory for microbial cultivation and analysis. After all the thorough experiments, you were only able to cultivate and study 36 microorganisms. However, based on the metagenomic analysis conducted, there are about 140 other species present in the samples collected. Why is this the case? Discuss and expound on the possible reason
A pure culture was inoculated onto a Mueller-Hinton agar plate. The Kirby-Bauer procedure was performed. One of the drugs tested showed a large zone of inhibition but also had small colonies growing within this zone. Further testing showed that these colonies were not the results of contamination. Why would these colonies be present within this zone of inhibition?
An inoculum of 106 bacterial cells was introduced into a flask of culture medium and growth monitored. No change was seen for 18 minutes (the lag phase), then growth occurred rapidly. After a further 87 minutes, the population had increased to 5.08 × 107 cells. What is the doubling time of the culture? Show your solution. (The 87-minute period is after the lag phase.)
After inoculating and incubating an agar slant from a pure broth culture of a bacterial species such as E. coli, which of the following would indicate an unsuccessful aseptic transfer? (Choose ALL that apply) a - There is fungal growth in the original broth culture tube. b- There is too much growth on the agar slant. c- There are colonies of similar morphology on the slant. d - There are red, yellow, and white colonies on the slant. e - There is no growth on the slant.
N. benthamiana will be infiltrated with a solution containing OD600=0.3 of each experimental Agro containing construct and OD600=0.1 of p19. Calculate the volume of cultures (V construct; V p19) needed according to the formulas: V construct = V final × 0.3/OD600; V p19 = V final × 0.1/OD600. One mL of infiltrate is often enough to complete a small experiment. How to plan your final volume accordingly?
Imagine that you have set up a Kirby Bauer experiment on Mueller Hinton agar (non-selective agar) in order to test if Escherichia coli is susceptible or resistant to Drug X. After 24 hours, you notice a zone of inhibition (clear zone) around your antibiotic disc and determine that E. coli is susceptible to Drug X. You then take a cotton swab and subculture a sample from this zone of inhibition (where no growth was apparent) onto a new agar plate without antibiotics and after 24 hours you see growth of E.coli. What can you conclude about Drug X?