Which of the following options is the correct genotype ratio for this cross? The cross is a female with hemophila and a male that does not have hemophilia. Select one: a. 2 XHXH 0 xHxh o xhxh 1XHY 1xhY O b. 0 XHXH 1xHxh 1 xhxh 1XHY 1xhY c. O XHXH 2xHxh o xhxh o xHY 2xhy O d. d. 1XHXH 0 xHxh 1xhxh 1XxHY 1xhY
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- As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progenyHemophilia is an X-linked recessive disorder and blood type is autosomal. If two healthy parents, one of which is blood type A and the other blood type B, produce a son who has hemophilia and is type O, what is the probability that their next child will be a son with hemophilia and blood type B? 1/2 3/16 1/4 1/8 1/16The most common form of colorblindness is a recessive, sex-linked hereditary con dition caused by a defect on the X chromosome. Females are XX, while males are XY. Individuals inherit one chromosome from each parent, with equal probability; for example, an individual has a 50% chance of inheriting their father's X chromosome, and a 50% chance of inheriting their father's Y chromosome. If a male has an X chromosome with the defect, he is colorblind. However, a female with only one defective X chromo some will not be colorblind. Thus, colorblindness is more common in males than females; 7% of males are colorblind but only 0.5% of females are colorblind. (a) Assume that the X chromosome with the wild-type allele is X+ and the one with the disease allele is X. What is the expected frequency of each possible female genotype: X+X+, X+X¯, and X-X-? What is the expected frequency of each possible male genotype: X+ Y and X-Y? (b) Suppose that two parents are not colorblind. What is the…
- Hemophilia is a sex-linked recessive trait. A male hemophiliac and phenotypically normal female have a son with hemophilia. They would like to have one more child. What is the probability of having a child without hemophilia? Explain using a Punnett square. Is it possible for a girl to be born with hemophilia? Explain.A man with hemophilia (a recessive, sex-linkedcondition) has a daughter without the condition.She marries a man who does not have hemophilia.What is the probability that their daughter willhave hemophilia? Their son? If they have foursons, what is the probability that all will be affected?Classical hemophilia is a sex-linked disease caused by a recessive gene on the X chromosome. (Hemophilia refers to diseases that cause delays in blood clotting.) If a woman who is acarrierof classical hemophilia has children with a normal male, give the ratios of the possible offspring with respect to classical hemophilia. Be sure to state both the genotypes and the phenotypes of each offspring. For genotypes, use X for a normal X chromosome, Xh for an X chromosome with the hemophilia gene, and Y for a normal Y chromosome. For phenotypes, if the offspring is female, be sure to state if homozygous normal, a carrier, or has the disease. If the offspring is a male, be sure to state if normal or has the disease.
- Hemophilia is a disease caused by a recessive allele (h), which is found on the X chromosome, non-hemophilia is (H). A normal man marries a woman that is heterozygous for the trait. Give the genotypes and phenotypes of all possible offspring?If an individual is bald, so you can't tell whether or not they have a widow's peak, but neither parent has a widow's peak, which genotypes are possible? Unable to determine Heterozygous Homozygous recessive Homozygous dominantIn the fictitious monster Lochnessius coolnameii, coat color is under the control of an autosomal gene, with white coat (W) dominant over black coat (w). The monster’s ability to produce horns is a sex-influenced trait, that is dominant in males but recessive in females. Let Horned = H, and hornless = h. Consider the cross of a homozygous white & horned male with a homozygous black & hornless female. What genotypes and phenotypes are expected in the F1? What genotypes and phenotypes are expected in the F2? In what ratios? Zappy is a horned white male. It was bred to the following four females, and the results are presented here: Mother Offspring Alcremie: hornless, black 1 horned white female Blissey: hornless, white 1 hornless black female Chansey: horned, black 1 horned, white female Delcattie: hornless, white 1 hornless, black male + 1 Horned white…
- Cystic fibrosis is a recessive human condition. A male with Cystic fibrosis and a woman with a dominant phenotype have sevral children, in which one displays Cystic fibrosis. What can you conclude about the genotype of the maternal parent and what is the probability that a child who does not display Cystic fibrosis is heterozygous?.Hemophilia is a blood-clotting disorder in humans that followsan X-linked recessive pattern of inheritance. A man with hemophilia and a woman without hemophilia have a daughter withhemophilia. If you let H represent the normal allele and h thehemophilia allele, what are the genotypes of the parents?a. Mother is XHXhand father is XhY.b. Mother is XhXhand father is XhY.c. Mother is XhXhand father is XHY.d. Mother is XHXhand father is XHYBryan has albinism, an autosomal recessive trait, which means he is homozygous recessive for albinism and his genotype is aa. Bryan's parents, Frank and Amy, do not have albinism however they must both be heterozygous. Bryan's sister, Allice, is a carrier for albinism. If Allice has offspring with Jim, who has no family history of albinism, what are the chances that their offspring are carriers for albinism? What are the chances that they children will get albinism? Use Punnett squares.