Which one of the following species has as many electrons as It has neutrons?A) 1HC) 14cE) 14c2+B) 40Ca2+D) 19F -

The species that have many electrons as it has neutrons has to be given.

Answered: Which one of the following species has…

Chemistry In Focus

7th Edition

ISBN:9781337399692

Author:Tro, Nivaldo J.

Publisher:Tro, Nivaldo J.

Chapter3: Atoms And Elements

Section: Chapter Questions

Problem 2SC

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Similar questions

Where are neutrons found in an atom? Are neutrons positively charged, negatively charged, or electrically uncharged?
Verify that the atomic weight of magnesium is 24.31, given the following information: 24Mg, mass = 23.985042 u; percent abundance = 78.99% 25Mg, mass = 24.985837 u; percent abundance = 10.00% 26Mg, mass = 25.982593 u; percent abundance = 11.01%
2-101 Complete the following table: Symbol Atomic number Atomic weight Mass number # of protons # of neutrons # of electrons H 0 Li 4 3 Al 26 58 78 17 20
Complete the following table. Name Symbol Atomic Number Mass Number Number of Neutrons 817O 8 9 iron 10 20 80244Pu 56 80202Hg cobalt 59 56 919F 28 chromium 26
Slaters rules are a way to estimate the effective nuclear charge experienced by an electron. In this approach, the shielding constant, S, is calculated. The effective nuclear charge is then the difference between S and the atomic number, Z. (Note that the results in Table 7.2 and Figure 7.2 were calculated in a slightly different way.) Z = Z S The shielding constant, S, is calculated using the following rules: (1) The electrons of an atom are grouped as follows: (1s) (2s, 2p) (3s, 3p) (3d) (4s, 4p) (4d), and so on. (2) Electrons in higher groups (to the right) do not shield those in the lower groups. (3) For ns and np valence electrons a) Electrons in the same ns, np group contribute 0.35 (for 1s 0.30 works better). b) Electrons in n 1 groups contribute 0.85. c) Electrons in n 2 groups (and lower) contribute 1.00. (4) For nd and nf electrons, electrons in the same nd or nf group contribute 0.35, and those in groups to the left contribute 1.00. As an example, let us calculate Z for the outermost electron of oxygen: S = (2 0.85) + (5 0.35) = 3.45 Z = 8 3.45 = 4.55 Here is a calculation for a d electron in Ni: Z = 28 [18 1.00] [7 0.35] = 7.55 and for an s electron in Ni: Z = 28 [10 1.00] [16 0.85] [1 0.35] = 4.05 (Here 3s, 3p, and 3d electrons are in the (n 1) groups.) a) Calculate Z for F and Ne. Relate the Z values for O, F, and Ne to their relative atomic radii and ionization energies. b) Calculate Z for one of the 3d electrons of Mn, and compare this with Z for one of the 4s electrons of the element. Do the Z values give us some insight into the ionization of Mn to give the cation?
2-27 If each atom in Problem 2-26 acquired two more neutrons, what element would each then be?
It is good practice to actively read the textbook and to try to verify claims that are made when you can. The following claim is made in your textbook: “. . . if the nucleus were the size of a grape, the electrons would be about 1 mile away on average.” Provide mathematical support for this statement.
True or false? Rutherford’s bombardment experiments with metal foil suggested that the particles were being deflected by coming near a large, positively charged atomic nucleus.
. The elements with atomic numbers of 93 or greater are referred to as the _________ elements.

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Which one of the following species has as many electrons as It has neutrons? A) 1H C) 14c E) 14c2+ B) 40Ca2+ D) 19F -