Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.76E
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Question
Why mass of glucose (c6h12o6) should dissolve in 11.5 kg of water to obtain a solution with a freezing point of -5.7 degrees c
Expert Solution
Step 1
Given
Mass of water = 11.5 Kg
Freezing point of solution = -5.7℃
Formula of Solute (Glucose)= C6H12O6
Therefore molar mass of Glucose = (6×12 ) +(12×1) + (6×16) gram /mole
=180 gm/ mole
Mass of Glucose =?
Kf (molal depression constant ) for water = 1.86 kg℃ / mol
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