To WUIK Outreactant. Use the relationship:mass of substancenumber of moles =mass of 1 mol of substanceorvolume of gas at s.t.p.number of moles of gas =22.4 dm3 mol-1of moles of the unknown, and hence the mass or volume at s.t.p.Worked example 4On heating, potassium chlorate( omposes into potassium chloride andoxygen:2KCIO;(s) → 2KCI(s) + 30,(g)9.8 g of KCIO3(s) are heated. Calculate:a the mass of KCl(s) formed3Bb the mass and volume, at s.t.p., of O,(g) formed. Worked example 7Barium chloride reacts with magnesium sulphate to form barium sulphate andmagnesium chloride:BaCl,(aq) + M9SO,(aq) → BaSO,(s) + MgCl,(aq)50 cm³ of 0.2 mol dm-3 BaCl,(aq) reacted according to the above equation.Calculate:the volume, in cm³, of 0.4 mol dm-3 MgSO,(aq) needed;ab the mass of BaSO,(s) formed.

The question is based on the concept of Reaction Stoichiometry. We have to calculate the mass of…

Answered: Worked example 4 On heating, potassium…

Worked example 4 On heating, potassium chlorate( composes into potassium chloride and oxygen: 2KCIO,(s) → 2KCI(s) + 30,(g) 9.8 g of KCIO;(s) are heated. Calculate: a the mass of KCl(s) formed;

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter5: Gases

Section: Chapter Questions

Problem 5.42PAE: 42 Air is often dry air, ignoring the water mole fractions of in dry air 0.7808 and 0.2095,...

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Question

To WUIK Out
reactant. Use the relationship:
mass of substance
number of moles =
mass of 1 mol of substance
or
volume of gas at s.t.p.
number of moles of gas =
22.4 dm3 mol-1
of moles of the unknown, and hence the mass or volume at s.t.p.
Worked example 4
On heating, potassium chlorate( omposes into potassium chloride and
oxygen:
2KCIO;(s) → 2KCI(s) + 30,(g)
9.8 g of KCIO3(s) are heated. Calculate:
a the mass of KCl(s) formed3B
b the mass and volume, at s.t.p., of O,(g) formed.

Worked example 7
Barium chloride reacts with magnesium sulphate to form barium sulphate and
magnesium chloride:
BaCl,(aq) + M9SO,(aq) → BaSO,(s) + MgCl,(aq)
50 cm³ of 0.2 mol dm-3 BaCl,(aq) reacted according to the above equation.
Calculate:
the volume, in cm³, of 0.4 mol dm-3 MgSO,(aq) needed;
a
b the mass of BaSO,(s) formed.

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