Write a code to calculate double func(int x,int y) recursively. When x <1 & ys 1 When x and y both are 1.3 (func(x, y – 1) + 2 * func(x - 1, y – 1)) even 2 * func(x – 1, y – 1) When x is even and y is func(x, y) = 3 odd When x is odd and y is (1.1 * func(x, y– 1)) (func(x- 1, y- 1) + 1) even When x and y are both odd
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- Consider the recursive procedure which computes the nth Fibonacci number is the one below. procedure Fl (n) //a function which returns the nth Fibonacci number.// if n < 2 then return(n) else return (F2(2,n,1,1)) endif end Fl procedure F2(i,n,x,y) if iis it correct ? Write a recursive function that returns the nth number in a fibonacci sequence when n is passed to function. The fibonacci sequence is like 0,1,1,2,3,5,8,13...... Answer: #include <iostream> using namespace std; int getFibonacci(int n) { if (n == 0 || n == 1) return n; else return getFibonacci(n - 1) + getFibonacci(n - 2); } int main() { int n = 7; int result = getFibonacci(n); cout << result; }Implement a recursive program that takes in a number and finds the square of that number through addition. For example if the number 3 is entered, you would add 3+3+3=9. If 4 is entered you would add 4+4+4+4=16. This program must be implemented using recursion to add the numbers together. I need the MIPS Code for the above.
- Write a program using a user defined recursive function to implement the following code segment. main() will call the recursive function and print the value of sum.int n, i, sum;n= last_two_digits_of_your_student_id+3;sum=0;for (i=n-3; i<=n; i++){sum=sum+i;}printf(“%d”, sum)please code in python Write a recursive function to add a positive integer b to another number a, add(a, b), where only the unit 1 can be added, For example add(5, 9) will return 14. The pseudocode is: # Base case: if b is 1, you can just return a + 1 # General case: otherwise, return the sum of 1 and what is returned by adding a and b - 1.c++ Implement a function that recursively calculates the nth number in the Fibonacci sequence of numbers. The Fibonacci sequence starts at 0 and 1. Each number thereafter is the sum of the two preceding numbers. This gives us the following first ten numbers: 0,1,1,3,5,8,13,21,34, .... Input Expected output0 01 17 139 34
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