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X(g) → X*(g) + e X+(g) → X²+(g) + e¯ X2+(g) → X³+(g) + e IE₁ = 740 kJ/mol IE₂ = 1450 kJ/mol IE3 = 7730 kJ/mol 6. Above are the first 3 ionization energies of a neutral element. Explain, in terms of Coulomb's law, why the ionization energy IE3 is much higher than the other two ionization energies.

X(g) → X*(g) + e X+(g) → X²+(g) + e¯ X2+(g) → X³+(g) + e IE₁ = 740 kJ/mol IE₂ = 1450 kJ/mol IE3 = 7730 kJ/mol 6. Above are the first 3 ionization energies of a neutral element. Explain, in terms of Coulomb's law, why the ionization energy IE3 is much higher than the other two ionization energies.

Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter2: Atomic Structure And Periodicity
Section: Chapter Questions
Problem 127E: Write equations corresponding to the following: a. the fourth ionization energy of Se b. the...
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X(g) → X*(g) + e X+(g) → X²+(g) + e¯ X²+(g) → X³+(g) + e IE₁ = 740 kJ/mol IE₂ = 1450 kJ/mol IE3 = 7730 kJ/mol 6. Above are the first 3 ionization energies of a neutral element. Explain, in terms of Coulomb's law, why the ionization energy IE3 is much higher than the other two ionization energies.
Transcribed Image Text:X(g) → X*(g) + e X+(g) → X²+(g) + e¯ X²+(g) → X³+(g) + e IE₁ = 740 kJ/mol IE₂ = 1450 kJ/mol IE3 = 7730 kJ/mol 6. Above are the first 3 ionization energies of a neutral element. Explain, in terms of Coulomb's law, why the ionization energy IE3 is much higher than the other two ionization energies.
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