YES / NO struct Node1 { uint16_t byte; }; YES / NO struct Node2 { int age; char name[64]; }; YES / NO struct Node3 { int age; char* name; }; struct Node4 { YES / NO| int data; struct Node4* next; };
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- struct Info { int id; float cost; }; Given the struct above, the following code segment will correctly declare and initialize an instance of that struct. Info myInfo = {10,4.99}; Group of answer choices True False ============== Consider the following code fragment. int a[] = {3, -5, 7, 12, 9}; int *ptr = a; *ptr = (*ptr) + 1; cout << *ptr; Group of answer choices 4 -5 3 Address of -5 =============== What will happen if I use new without delete? Group of answer choices The program will never compile The program will never run The program will run fine without memory leak None of theseAssume that following initialization is given in your structure allStudent[5] and data is sorted based on name field, struct studInfo { int stNr; char name[10] ; int grade; }; int main() // already sorted base on name field { struct studInfo allStudent[5]={ 97790, “ADEM” , 77, 963582, “AFGAR” , 85, 957434 ,”AHMED”, 100, 921229 ,”BAKI” , 65, 971280 ,”ZEKI” , 88}; int n=5;/* Total number of students*/ char givenName[10]; gets(givenName); k=binarySearch(………..); … …. sortBubble(……); .. .. .. return 0; } A) Write a C function named as binarySearch() and search a given student(get a name information from the monitor) in the given array allStudent[]…1. Struct (Optional: 1 point)1) Use the following abstract data type called Rectangle to get the length and width from the user. 2) Display the length, width, area, perimeter, and whether the rectangle is a square.struct Rectangle{float length;float width;float area;float perimeter;};2. Linked List (Optional: 1 point)Modify the following program to make a node containing data values of int, char, and string:#include <iostream>using namespace std;struct Node { int data; struct Node *next; };struct Node* head = nullptr; //or NULL or 0;void insert(int new_data) { struct Node* new_node = (struct Node*) new (struct Node); new_node->data = new_data; new_node->next = head; head = new_node; } void display() { struct Node* ptr;ptr = head;while (ptr != NULL) { cout<< ptr->data <<" "; ptr = ptr->next; } } int main() { insert(2);display(); return 0; } 1) Create a linked list of ten nodes (each node contains the three types of data values). 2) Display the data values…
- create a prog that will compute the final grade for a certain student and will display the final grade and a remark if it is passed or failedPass = 75 aboveFailed = 74 belowCS= 60% quiz + 40 assignmentPG =[ 2(Pcs) + PE] / 3TMG = [2(Mcs) +ME] /3MG = [2(TMG) + PG] / 3TFG = Fcs +ME + SFEFG = [2(TFG) + MG ] / 3sample output:enter name of student: Cruzenter quiz Score: 75enter assignment Score: 75enter PE Score: 75PG of Cruz is : 75enter Mquiz Score: 75enter Massignment Score: 75enter ME Score: 75MG of Cruz is: 75enter Fquiz Score: 75enter Fassignment Score: 75enter SFE Score: 75enter FE Score: 75MG of Cruz is: 75FG of Cruz is : 75congrats you PASS**Print the order of insertion to the screen for the code below** #include<iostream> using namespace std; struct node { public: int data; node* left; node* right; }; class BST { public: node* insert(node* , int); void Preorder(node*); void Inorder(node*); void Postorder(node*); }; node* get_new_node(int n) { node* temp = new node; temp->data = n; temp->left = NULL; temp->right = NULL; return temp; } node* BST::insert(node* root , int data) { if(root == NULL) { root = get_new_node(data); } else if (data <= root->data) { root->left = insert(root->left , data); } else { root->right = insert(root->right , data); } return root; } void BST::Preorder(node* root) { if(root == NULL){ return ; } else { cout << root -> data << " "; Preorder(root -> left); Preorder(root -> right); } } void BST::Inorder(node* root) { if(root == NULL){ return ; } else { Inorder(root -> left); cout<<root -> data << " "; Inorder(root…Write a display function and delete function in the following code: Declare the libraries Declare the struct Node void create (int A[], int n) { int i; struct Node *t, *last; first = (struct Node *)malloc(sizeof(struct Node)); first->data=A[0]; first->next=NULL; last=first; for(i=1;i<n;i++) { t=(struct Node *)malloc(sizeof(struct Node)); t->data=A[i]; t->next=NULL; last->next=t; last=t; } } Write the Delete Function Write the display function int main() { int A[]={10,20,30,40,50}; create(A,5); Delete(first,4); Display(first); return 0; }
- 4) A)Trace(Draw data structure that you obtained) ./* That's what the teacher said :( can u check the problem again, pls */ B)List the output of the following program. #include <stdio.h>#include <stdlib.h>#include <string.h> struct nodetype {struct nodetype *left ;int info ;struct nodetype *right;}; typedef struct nodetype NODE; typedef NODE *NODEPTR; void main(){ NODEPTR root , p , q;root=NULL; int sevenNum[8]={65 , 52 , 45 , 27 , 33 , 79 , 26 , 48};int number, i=0;number=sevenNum[i];root=maketree(number);do{number=sevenNum[++i];p=q=root; while(q!=NULL){p=q;if (number <p->info)q = p->left;elseq = p->right;}q=maketree(number); if (number<p->info) p->left=q;elsep->right=q;} while(i!=8); printf("X Traversing \n "); xtrav(root);} void xtrav(NODEPTR tree){if (tree != NULL){xtrav(tree->left);xtrav(tree->right);printf("%d \n", tree->info);}} NODEPTR maketree(int x){NODEPTR p;p=(NODEPTR) malloc(sizeof(struct…this is code #include <iostream> using namespace std; struct Node { int data; struct Node *next; }; struct Node* head = NULL; void insert(int new_data) { struct Node* new_node = (struct Node*) malloc(sizeof(struct Node)); new_node->data = new_data; new_node->next = head; head = new_node; } void display() { struct Node* ptr; ptr = head; while (ptr != NULL) { cout<< ptr->data <<" "; ptr = ptr->next; } } int main() { insert(3); insert(1); insert(7); insert(2); insert(9); cout<<"The linked list is: "; display(); return 0; } i want Re-implement it on doubly linked list take in account the set-position method and the operator overload and coy constructor and destructor ? in c++Incoroporate or use below code as reference #include <stdio.h>#include <stdlib.h>#include <time.h> typedef struct node_struct {int item;struct node_struct *next;} node; /*** 10->NULL* We want to insert 20* First call ([10], 20) [has not finished yet]* {10, {20, NULL}}*** Second call (NULL, 20) {20, NULL}*/node* insert_unordered(node *temp_root, int item) {if (temp_root == NULL) {temp_root = malloc(sizeof(node));temp_root->item = item;temp_root->next = NULL;} else {temp_root->next = insert_unordered(temp_root->next, item);}return temp_root;} /*** This is atypical linked list because* (i) it does not allow duplicates and* (ii) it is sorted* 10->20, i want to insert 15* 10->15->20**/
- C++: Consider the following code: struct node { int data; node *next; }; node myNode; node *p = &myNode; Which of these will set member variable data of myNode to the value 7? A) node->data = 7; B) p->node = 7; C) p.node = 7; D) myNode.data = 7;Here are some errors in my code please correct these errors and give the right code with proper comments. The code is in C++ language. #include <bits/stdc++.h> using namespace std; struct Node { int data; Node left; Node right; }; // Utility function to create a new Tree Node Node* newNode(int val) { Node* temp = new Node; temp->data = val; temp->left = NULL; temp->right = NULL; return ; } // Function to Build Tree Node* buildTree(string ) { // Corner Case if(str.length() == 0 || str[0] == 'N') return NULL; // Creating vector of strings from input // string after spliting by space vector<string> i; istringstream iss(str); for(string str; iss >> str; ) ip.push_back(str); // Create the root of the tree Node* root = newNode(stoi(ip[0])); // Push the root to the queue queue<Node*> queue; queue.push(); //…In C++, Define struct StudentInfo; maintain records in a vector<StudentInfo>. Program prompts for and fetches data, builds vector of student records, sorts by name, calculates max and min grades (no names, just max and min numbers), class average, prints summarizing data along with class roll and grades. Test program. Note: add constructors (default/parameterized wherever applicable)