You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.57. You use a significance level of a = 0.001. Ho:p = 0.57 H1:p > 0.57 You obtain a sample of size n = 331 in which there are 211 successes. (1) What is the critical value for this test? CV = (Report answer accurate to three decimal

You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.57. You use a significance level of a = 0.001. Ho:p = 0.57 H1:p > 0.57 You obtain a sample of size n = 331 in which there are 211 successes. (1) What is the critical value for this test? CV = (Report answer accurate to three decimal

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A major credit card company is interested in the proportion of individuals who use a competitor’s credit card. Their null hypothesis is H0: p=0.65H0: p=0.65, and based on a sample they find a sample proportion of 0.70 and a pp-value of 0.053. Is there convincing statistical evidence at the 0.05 level of significance that the true proportion of individuals who use the competitor’s card is actually greater than 0.65 ?
My original question has already been answered, however, in Step 2 of the Expert Answer I would like clarification on how to compute the critical values manually - without the use of EXCEL, as mentioned in the respnse, so I need to know what formula do I use? Question: Prior to assessment of the outcome, the researchers did a manipulation check. Members of Groups 1 and 2 rated the attractiveness (on a 1 to 9 scale, with 9 being the most attractive) of the person in the photo. They reported that for the attractive photo, M = 7.53; for the unattractive photo, M = 3.20, F(1, 108) = 184.29. Was this difference statistically significant (using a = .05)? Expert Answer Step 1 It is given that the F-test statistic is 184.29, the degrees of freedom for first and second groups are 1 and 108, and the level of significance is 0.05. State the appropriate hypothesis: Null hypothesis: H0 : There is no difference between two groups. Alternative hypothesis: Ha : There is a difference between…
a) Justify the choice of test procedure. b) Can a student's t-test on paired samples be used as a test procedure for the given problem? Why or why not? c) Give the appropriate conclusion at 5% level of significance: At alpha = 0.05, ______.
In experimental situations, care is taken to control for as many factors as possible which might influence the results so as to increase the confidence of the causal relationship between the independent and dependent variables. In cases where results are of marginal statistical significance, say just less than 0.05, how might this level of control affect the ability to apply the results in real world settings?
A major credit card company is interested in the proportion of individuals who use a competitor’s credit card. Their null hypothesis is H0: p=0.65H0: p=0.65, and based on a sample they find a sample proportion of 0.70 and a pp-value of 0.053. Is there convincing statistical evidence at the 0.05 level of significance that the true proportion of individuals who use the competitor’s card is actually greater than 0.65 ? Yes, because the sample proportion 0.70 is greater than the hypothesized proportion 0.65. A Yes, because the pp-value 0.053 is greater than the significance level 0.05. B No, because the sample proportion 0.70 is greater than the hypothesized proportion 0.65. C No, since the sample proportion 0.70 is exactly 0.05 away from the hypothesized proportion 0.65. D No, because the pp-value 0.053 is greater than the significance level 0.05.
You are testing the null hypothesis that there is no linear relationship between two variables, X and Y. From your sample of n=18, you determine that b1=5.2 and Sb1=1.2. a. What is the value of tSTAT? b. At the α=0.05 level of significance, what are the critical values? c. Based on your answers to (a) and (b), what statistical decision should you make? d. Construct a 95% confidence interval estimate of the population slope, β1.
What would you conclude based on an α=0.05 level? We reject the null hypothesis and do not accept the alternative hypothesis since there is sufficient evidence that the proportion of all vehicles that meet or exceed current fuel economy standards is greater than 90% due to the p-value being greater than the α level. Explain the results of your hypothesis test. What does the p-value signify? Would you say the observed outcome was unusual? If so, how unusual was the outcome?
The local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs at minimum number of swimmers to sign up in order to be cost effective. Last year’s data showed that during 8 swim sessions the average number of entry-level swimmers attending was 15. Suppose the instructor wants to conduct a hypothesis test. The alternative hypothesis for this hypothesis test is: "the population mean is less than 15". The sample size is 8, σ is known, and alpha =.05, the critical value of z is?
A study on the effects of color on easing test anxiety compared anxiety test scores of participants who completed a test printed on either soft yellow paper or harsh green paper. The scores for the 10 participants who completed the yellow and the 10 participants who completed it on the green paper are below (Table 5). Using an alpha level of .05, do participants who use the yellow paper report lower test anxiety than those who wrote it on the harsh green paper? Table 5. Anxiety scores
. A taxi company has been using Brand A tires, and the distribution of kilometers to wear-out has been found to be approximately normal with mean =114,000 and σ = 11,600. Now it tries 12 tires of Brand B and finds a sample mean 117,200. Test at the 5% level of significance to see whether there is a significant difference (positive or negative) in kilometers to wear-out between Brand A and Brand B. In the problem above, if the true kilometers to wear-out is 114,000, what is the 95% confidence interval for sample means? First show how to get the critical z values.
Is the proportion of wildfires caused by humans in the south different from the proportion of wildfires caused by humans in the west? 394 of the 533 randomly selected wildfires looked at in the south were caused by humans while 388 of the 554 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the = 0.01 level of significance? For this study, we should use Select an answer z-test for the difference between two population proportions t-test for the difference between two dependent population means z-test for a population proportion t-test for the difference between two independent population means t-test for a population mean The null and alternative hypotheses would be: Select an answer p1 μ1 Select an answer > ≠ < = Select an answer μ2 p2 (please enter a decimal) Select an answer p1 μ1 Select an answer > = < ≠ Select an answer p2 μ2 (Please enter a decimal) The test statistic ? z t = (please show your…
A large manufacturing company investigated the service it received from its suppliers and discovered that, in the past, 44% of all material shipments were received late. However, the company recently installed a just-in-time system in which suppliers are linked more closely to the manufacturing process. A random sample of 170 deliveries since the just-in-time system was installed reveals that 34 deliveries were late. If we want to test whether the proportion of late deliveries was reduced signicantly at = 0:01 the null and alternative hypotheses are a. Null hypothesis (H0) b. Alternative hypothesis (HA)