You can click on the Review link to access the se A sodium nitrate solution is 14.4 % NaNO3 by mass and has a density of 1.02 g/mL. Part A Calculate the molarity of the solution. O 1.73 M O 0.579 M O 14.7 M O 1.66 M
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- You are given the suggestion that a 0.15 ppm quinine aqueous solution is a good concentration to shoot for in the experiments, but quinine fluoresces best when it is acidified to 0.10 M H2SO4. Describe how to make 100 mL of the recommended solution starting with quinine sulfate (actually, quinine hemisulfate salt monohydrate). Assume you also have 1.0 M sulfuric acid and de-ionized water.Dilute the stock solution: Using the solutions in the burets, carefully measure the following quantities of Co(NO3)2 solution and water into 5 large test tubes, to a total of 5.00 mL in each test tube. Yes, the optional video says to make 10.00 mL total, but 5.00 mL is sufficient at this time and generates less waste. Use the buret to measure the cobalt solution and the water. Test tube No. 1 2 3 4 5 mL Co2+ Soln 1.00 2.00 3.00 4.00 5.00 mL H2O 4.00 3.00 2.00 1.00 0.00 Total mL 5.00 5.00 5.00 5.00 5.00 Mix each test tube thoroughly: hold the top of the tube and mix the bottom well. Transfer a portion of each diluted sample into a clean, dry sample cuvette. fill the concentration table and do calculations pleaseYou are supplied with the following: / Jy word voorsien van die volgende: NaCl(Mr= 58,443 g /mol) 2.5MTris-Cl, pH 8 solution /oplossing (1 Litre) EDTA,natriumsout(Mr= 380,2g/mol) 10% sodium dodecyl sulphate solution / natriumdodecyl sulfaat oplossing Proteïnase K solution / oplossing (50 mg dissolved / opgelos in 1 ml ddH2O) You need a digestion buffer consisting of the following: / Jy moet 'n verteringsbuffer op maak wat uit die volgende bestaan: 15m M NaCl 75 mM Tris-Cl,pH 8 16 mM EDTA,pH 8 0.8% sodium sulphate / natrium dodecyl sulfaat 0,75 mg/ml proteïnase K How will you prepare 500 ml of the digestion buffer? Show all your steps and calculations. Remember to explain exactly how you will make it up.
- Which statement is true? Statement 1: The two phases in the liquid/liquid extraction are aqueous layer and organic layerStatement 2: The distribution coefficient is the ratio of the equilibrium concentrations of the analyte in the two immiscible liquidsVolumetric Analysis The mass of KHC8H4O4 is measured to the nearest milligram; however, the volume of water in which it is dissolved is never of concern—water is even added to the wall of the Erlenmeyer flask during the titration. Explain why water added to the KHC8H4O4 has no effect on the data, whereas water added to the NaOH solution, may drastically affect the data.You are asked to make the compound [Ni(en)3]SO4. - By using 2.611 grams of NiSO4*6H2O (s) you dissolve the sample in deionized water completely. - You then add 10ml of 25% en into the solution and mix until a single product forms - When the addition of the en is complete, you then add 15ml of ethanol and mix. - using a bench vaccine and Buchner funnel, you filter the precipitate while carefully breaking up the solid until powder form. - the product is the washed with 15ml of ethanol and 15ml of acetone. Powder the solid and leave to dry Which is the limiting reagent? Write a balanced chemical equation for the reaction. How many miles of the product can you theoretically prepare?
- How much amount (in grams) do you need to prepare the following solutions 500.0 mL 0.1000 M stock EDTA solution from Na2H2EDTA•2H2O (FW=372.24) and MgCl2•6H2O crystals 100.0 mL 0.0500 M stock Ca2+ solution from pure CaCO3 (FW=100.09) and concentrated HCl 250 mL 1.0 M NH3-NH4+ pH 10 buffer solution from NH4Cl and NH3A 25.00 mL sample of an aqueous solution Y is extracted with 50.00 mL of hexane. After extraction, it was found that 94.12% of solute Y was successfully removed from the aqueous solution. Calculate: i. The distribution constant for this separation The initial concentration of Y if 1.77 mmol Y remains in aqueous solution after extraction. iii. The concentration of Y in BOTH phases after extractionPrepare 100.00 mL of a solution with ALL the following chemicals into together; CHEMICALS PROVIDED solid FeCl3 6H2O, iron(II) chloride hexahydrate (source of FeCl3) dilute hydrochloric acid in the rack – 3.0 M solid sodium salicylate – 99.7% assay Concentrations needed in the 100mL solution FeCl3: 0.020 M HCl: 0.050 M Salicylate (mg/L): 40.25 PLEASE SHOW HOW TO CALUATE AND WORK. The only equations you will need to use are the equations for molarity and dilutions.
- 5.00 mL of stock solution is diluted to 25.00 mL, producing solution ALPHA. 10.00 mL of solution ALPHA is diluted to 25.00 mL, resulting in solution BETA. 10.00 mL of solution BETA is then diluted to 25.00 mL, producing solution GAMMA. dilution factor for ALPHA from stock solution = 0.167 dilution factor for BETA from ALPHA solution = 0.0476 part c and d?Prepare 25ppm of Cd (NO3 )2.4H2O in a 500ml from 1000ppm stock solution of Cd (NO3)2.4H2OUse the attached pictures to help fill in the rest of the data. Please note that I used 0.79g of KMnO4 to prepare 250ml of 0.02M solution to titrate the ferrous ammonium sulfate. The approximate 1g of ferrous ammonium sulfate contained 25ml of distilled water and 10ml of 1M H2SO4 : H3PO4 to help dissolve the mixture for part one. For part two, the same steps were used however, we are to determin the amount of Fe in the sample. Please show and explain your work for each trail. Thank you!
