Question

You hold a softball with a weight of 1.80 N in your hand as shown in the figure. Your arm is moving, but at the instant shown, your arm is horizontal. Consider your forearm and hand to be a uniform rod with a mass of 1.65 kg and the distance between your elbow joint and the ball in your hand is

2L = 26.0 cm.

Your biceps exerts an upward, vertical force of 13.5 N on your forearm and is attached a distance of d = 2.60 cm from your elbow.

(a) Using your elbow joint as the axis of rotation, determine the magnitude of the net torque acting about your elbow due to the weight of your forearm/hand, the weight of the ball, and the force applied by your bicep.

N · m

N · m

(b) In which direction will your forearm and hand rotate, given the signed value of the net torque calculated in part (a)?

clockwise

counterclockwise

no rotation

Step 1

The net torque acting on the elbow is the sum of the torque acting on biceps, hand and the ball.

Torque is a measure of the force that can cause an object to rotate about an axis. Figure shows the direction of the force, m be the mass of the ball.

Step 2

The torque acting along the bicep will be in opposite direction to the other torques. The magnitude of the torque is the product of the force acting on the object to the length.

Step 3

Tagged in

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