Concept explainers
The Iron Cross When a gymnast weighing 750 N executes the iron cross as in Figure l*N.91a, the primary muscles involved in supporting this position are the latissimus dorsi (“lats") and the pectoralis major (“pecs"). The rings exert an upward force on the aims and support the weight of the gymnast. The force exerted by the shoulder joint on the arm is labeled
Trending nowThis is a popular solution!
Chapter 8 Solutions
College Physics
Additional Science Textbook Solutions
Essential University Physics (3rd Edition)
The Cosmic Perspective (8th Edition)
Physical Universe
Conceptual Physics: The High School Physics Program
Introduction to Electrodynamics
- A crane of mass m1 = 3 000 kg supports a load of mass m2 = 10 000 kg as shown in Figure P10.36. The crane is pivoted with a frictionless pin at A and rests against a smooth support at B. Find the reaction forces at (a) point A and (b) point B. Figure P10.36arrow_forwardA beam resting on two pivots has a length of L = 6.00 m and mass M = 91.0 kg.The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 62.0 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (b) Where is the woman when the normal force n1 is the greatest?x = m(c) What is n1 when the beam is about to tip? N(d) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. N(e) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.x = m(f) Check the answer to part (e) by computing torques around the first pivot point.x = marrow_forwardThe distance from the center of the breastbone to a man’s hand, with the arm outstretched and horizontal to the floor, is 1.00 m. The man is holding a 9.05-kg dumbbell, oriented vertically, in his hand, with the arm horizontal. What is the torque due to this weight about a horizontal axis through the breastbone perpendicular to his chest? ____N⋅marrow_forward
- Why is the following situation impossible? A uniform beam of mass mb = 3.00 kg and length ℓ = 1.00 m supports blocks with masses m1 = 5.00 kg and m2 = 15.0 kg at two positions as shown. The beam rests on two triangular blocks, with point P a distance d = 0.300 m to the right of the center of gravity of the beam. The position of the object of mass m2 is adjusted along the length of the beam until the normal force on the beam at O is zero.arrow_forwardThere are four forces acting on a pole, A = 10i N, B = 20j N, C = -30j N, D = -40i N. What should be the magnitude of force E that must be exerted on the pole to maintain static equilibrium? Note: i and j are unit vectors a. 24.65 N b. 31.62 N c. 46.20 N d. 52.78 N e. No Answerarrow_forwardA 9 kg weight is hanging from one end of a uniform rod of 12 m length. If the rod rests horizontally on a pole at 5.25 m from that end, what is the weight of the rod? (i) 65 kg (ii) 61 kg (iii) 63 kg (iv) 47.25 kgarrow_forward
- Two children are playing on a seesaw trying to balance. If the child on the left sits 1.5 meters away from the fulcrum and weighs 25 kg, and the child on the right weighs 35 kg, how far away from the pivot point will the child on the right have to sit? A. 1.5 m B. 0.75 m C. 1.75 m D. 1.07 marrow_forwardParallel axis theorem transfer the moment of inertia of a area from its own axis to another parallel axis Select one: True False A system of coplanar forces acting on a rigid body can be reduced to a. One force only b. None of the above c. One force and one couple only d. One couple onlyarrow_forwardan 80-kg man is sitting on the right side of the plank, 1.25m away from the fulcrum. While on the left side of the plank, a 30-kg girl and a 20-kg boy are both seated 2.00 and 1.75m away from the fulcrum, respectively. A mystery object C is also placed on the left side of the plank with a lever arm of 1.0m. To make the system in equilibrium, another mystery object A is placed on the right side of the plank, 0.5m away from the fulcrum. Use the second condition for equilibrium to find the Torques of objects A and C.arrow_forward
- an 80-kg man is sitting on the right side of the plank, 0.75 away from the fulcrum. While on the left side of the plank, a 30-kg girl and a 20-kg boy are both seated 1.50m and 2.00m away from the fulcrum, respectively. A mystery object C is also placed on the left side of the plank with a lever arm of 1.0m. To make the system in equilibrium, another mystery object A is placed on the right side of the plank, 2.00m away from the fulcrum. Use the second condition for equilibrium to arrive at equations showing the relationship of the masses of mystery objects A and C, then find their masses using the equations.arrow_forwardA beam resting on two pivots has a length of L = 6.00 m and mass M = 88.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 61.0 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. Where is the woman when the normal force n1 is the greatest? X=0 c. (c) What is n1 when the beam is about to tip? 0 (d) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. (e) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip (f) Check the answer to part (e) by computing torques around the first pivot point x =arrow_forwardA beam resting on two pivots has a length of L = 6.00 m and mass M = 92.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 62.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (c) Using the (force equation of equilibrium to find the value of n2 when the beam is about to tip). and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.x = z____m(d) Check the answer to part (c) by computing torques around the first pivot point.x = ____m(e) Except for possible slight differences due to rounding, is the answer the same? Yes or Noarrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning