You wish to find the enthalpy for the reaction 6 GeI₄ (s) + 14 NH₄I (s) → 3 Ge₂H₆ (l) + 7 N₂ (g) + 38 HI (g) Given the following equations Equation 1: 2 Ge (s) + 3 H₂ (g) → Ge₂H₆ (l) ∆H = 137.3 kJ/mol Equation 2: Ge (s) + 4 HI (g) → GeI₄ (s) + 2 H₂(g) ∆H = -247.8 kJ/mol Equation 3: 2 NH₄I (s) → N₂ (g) + 2 HI (g) + 3 H₂(g) ∆H = 455.8 kJ/mol

Chemistry: The Molecular Science
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Chapter4: Energy And Chemical Reactions
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You wish to find the enthalpy for the reaction
6 GeI₄ (s) + 14 NH₄I (s) → 3 Ge₂H₆ (l) + 7 N₂ (g) + 38 HI (g)
Given the following equations
Equation 1: 2 Ge (s) + 3 H₂ (g) → Ge₂H₆ (l) ∆H = 137.3 kJ/mol
Equation 2: Ge (s) + 4 HI (g) → GeI₄ (s) + 2 H₂(g) ∆H = -247.8 kJ/mol Equation 3: 2 NH₄I (s) → N₂ (g) + 2 HI (g) + 3 H₂(g) ∆H = 455.8 kJ/mol
 
G. 6 Ge (s) + 9 H₂ (g) → 3 Ge₂H₆ (l) 6 GeI₄ (s) + 12 H₂(g) → 6 Ge (s) + 24 HI (g) 14 NH₄I (s) → 7 N₂ (g) + 14 HI (g) + 21 H₂(g)
When you add the above three chemical equations together, what species will cancel out completely?
 
H. Calculate the enthalpy for 6 GeI₄ (s) + 14 NH₄I (s) → 3 Ge₂H₆ (l) + 7 N₂ (g) + 38 HI (g).
 
 
 
 
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