   Chapter 10, Problem 68AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
5 views

# Calculate the amount of energy required (in calories) to heat 145 g of water from 22.3 °C to 75.0 °C.

Interpretation Introduction

Interpretation:

The heat required in calories to raise the temperature of water should be calculated.

Concept Introduction:

The specific heat is defined as the amount of heat per unit mass needed to raise the temperature by one degree Celsius.

It is mathematically represented as follows:

Q=msΔT

Here, Q is heat, m is mass, s is specific heat capacity and ΔT is change in temperature.

Explanation

Given Information:

The mass of water is 145 g, initial temperature is 22.3 C and final temperature is 75.0 C

Calculation:

From table 10.1, the specific heat capacity of water (liquid) is 4.184 J/g C

The heat required can be calculated using the following equation:

Q=msΔT

Or,

Q=ms(T2T1)

On putting the values,

Q=(145 g)(4.184 J/g C)(75 C22

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