   # The term proof is defined as twice the percent by volume of pure ethanol in solution. Thus, a solution that is 95% (by volume) ethanol is 190 proof. What is the molarity of ethanol in a 92 proof ethanol-water solution? Assume the density of ethanol, C 2 H 5 OH, is 0.79 g/cm 3 and the density of water is 1.0 g/cm 3 . ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 10, Problem 96AE
Textbook Problem
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## The term proof is defined as twice the percent by volume of pure ethanol in solution. Thus, a solution that is 95% (by volume) ethanol is 190 proof. What is the molarity of ethanol in a 92 proof ethanol-water solution? Assume the density of ethanol, C2H5OH, is 0.79 g/cm3 and the density of water is 1.0 g/cm3.

Interpretation Introduction

Interpretation: The given molarity of Ethanol has to be calculated.

Concept Introduction:

Concentration can be defined in terms of molarity as moles of solute per volume of solution in litres. It can be given by the expression,

Molarity=massofsolutevolumeofsolution

### Explanation of Solution

Record the given data from question

Density of Ethanol= 0.79g/cm3

Volume of Ethanol=

46mL

Molecular weight of Ethanol=

46.07g/mole

To find the mole of Ethanol

A 92 proof ethanol solution is 46% C2H5OH by volume. Assume 100mL of solution:

moleofEthanol=46mLC2H5OH×0

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