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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A gas is enclosed in a container fitted with a piston of cross-sectional area 0.150 m2. The pressure of the gas is maintained at 6.00 × 103 Pa as the piston moves inward 20.0 cm. (a) Calculate the work done by the gas. (b) If the internal energy of the gas decreases by 8.00 J, find the amount of energy removed from the system by heat during the compression.

(a)

To determine
The work done by the gas.

Explanation

Section1:

To determine: the change in volume of the gas.

Answer: change in volume of the gas is 3.00×102m3 .

Explanation:

Given Info:

Cross-sectional area of the piston is 0.150m2 .

The movement of piston inward is 20cm .

Formula to calculate the change in volume is,

ΔV=VfVi=A(ΔL)

    • A is the area of the piston
    • ΔL is the movement of piston inward

Substitute 0.150m2 for A and 20cm for ΔL to find the change in volume,

ΔU=(0.150m2)(0.200m)=3.00×102m3

Thus, change in volume of the gas is 3.00×102m3

Conclusion:

From Equation (I), change in volume of the gas is 3

(b)

To determine
the amount of energy removed from the system by heat.

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