The equilibrium constant, K, for the following reaction is 1.80×10-2 at 510 K.PCl5(g) PCl3(g) + Cl2(g)An equilibrium mixture of the three gases in a 7.99 L container at 510 K contains 0.377 M PCl5, 8.23×10-2 M PCl3 and 8.23×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 18.5 L?[PCl5]= M[PCl3]= M[Cl2]= M

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Answered: The equilibrium constant, K, for the…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 95QRT

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The equilibrium constant, K, for the following reaction is 1.80×10^-2 at 510 K.

PCl₅(g) PCl₃(g) + Cl₂(g)

An equilibrium mixture of the three gases in a 7.99 L container at 510 K contains 0.377 M PCl₅, 8.23×10^-2 M PCl₃ and 8.23×10^-2 M Cl₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 18.5 L?

[PCl₅]	=	M
[PCl₃]	=	M
[Cl₂]	=	M

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