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The equilibrium constant, K, for the following reaction is 1.20x10-2 at 500 K. PCI5(g) PC13(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00L flask at 500 K contains 0.295 M PCI,, 5.95x10-2 M PCIą and 5.95x10-2 M Cl,. What will be the concentrations of the three gases once equilibrium has been reestablished, if 4.64x102 mol of PCI3(g) is added to the flask? [PClg] =| [PCI3] = [C2] =| M M M

The equilibrium constant, K, for the following reaction is 1.20x10-2 at 500 K. PCI5(g) PC13(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00L flask at 500 K contains 0.295 M PCI,, 5.95x10-2 M PCIą and 5.95x10-2 M Cl,. What will be the concentrations of the three gases once equilibrium has been reestablished, if 4.64x102 mol of PCI3(g) is added to the flask? [PClg] =| [PCI3] = [C2] =| M M M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K. PCI5(g) =PCl;(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.295 M PCI5, 5.95×10-² M PCI3 and 5.95×102M Cl. What will be the concentrations of the three gases once equilibrium has been reestablished, if 4.64×10-2 mol of PCI3(g) is added to the flask? [PCI5] M [PCI3] = M [C2] M
Transcribed Image Text:The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K. PCI5(g) =PCl;(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.295 M PCI5, 5.95×10-² M PCI3 and 5.95×102M Cl. What will be the concentrations of the three gases once equilibrium has been reestablished, if 4.64×10-2 mol of PCI3(g) is added to the flask? [PCI5] M [PCI3] = M [C2] M
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