menu
bartleby
search
close search
Hit Return to see all results
close solutoin list

Peptide decomposition is one of the key processes of digestion, where a peptide bond is broken into an acid group and an amine group. We can describe this reaction as follows: Peptide ( a q ) + H 2 O ( l ) ⇌ acid group ( a q ) + amine g r o u p ( a q ) If we place 1.0 mole of peptide into 1.0 L water, what will be the equilibrium concentrations of all species in this reaction? Assume the K value for this reaction is 3 .1 × 10 −5 .

BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

Solutions

Chapter
Section
BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 12, Problem 88AE
Textbook Problem
18 views

Peptide decomposition is one of the key processes of digestion, where a peptide bond is broken into an acid group and an amine group. We can describe this reaction as follows:

Peptide ( a q ) + H 2 O ( l ) acid group ( a q ) + amine g r o u p ( a q )

If we place 1.0 mole of peptide into 1.0 L water, what will be the equilibrium concentrations of all species in this reaction? Assume the K value for this reaction is 3 .1 × 10−5.

Interpretation Introduction

Interpretation: The reaction involving the decomposition of a peptide bond into an acid group and an amine group is given. The equilibrium concentrations of all the species involved in the reaction when 1.0mole of peptide is placed in 1.0L of water are to be calculated.

Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction.

When the equilibrium constant is expressed in terms of concentration, it is represented as K .

To determine: The equilibrium concentrations of all the species involved in the given reaction.

Explanation of Solution

Explanation

Given

The stated reaction is,

Peptide(aq)+H2O(l)acidgroup(aq)+aminegroup(aq)

The initial number of moles of peptide is 1.0mole.

The value of the equilibrium constant for the reaction is 3.1×105.

At equilibrium, the equilibrium ratio is expressed by the formula,

K=ConcentrationofproductsConcentrationofreactants

Where,

  • K is the equilibrium constant.

The equilibrium constant expression for the given reaction is,

K=[acidgroup][aminegroup][Peptide] (1)

The amount of the peptide that reacted till the equilibrium stage is 0.0056M_.

The initial concentration of the given peptide is 1.0mol/L that is 1.0M.

The amount of the peptide that reacted till the equilibrium stage is assumed to be x .

The equilibrium concentrations are represented as,

Peptide(aq)+H2O(l)acidgroup(aq)+aminegroup(aq)Initialconcentration1.000Change-x+x+xEquilibriumconcentration1.0-xxx

H2O is present in the liquid state and hence it does not affect the value of the equilibrium constant.

According to the ICE table formed,

The equilibrium concentration of the peptide is (1.0x)M.

The equilibrium concentration of the acid group is xM.

The equilibrium concentration of the amine group is xM.

Substitute the equilibrium concentration values of the peptide, the acid group and the amine group in equation (1).

The equilibrium constant expression for the given reaction is,

K=[acidgroup][aminegroup][Peptide]=[x][x][1.0x]=[x]2[1.0x]

The value of the equilibrium constant (K) for the reaction is given to be 3

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Chapter 12 Solutions

Chemistry: An Atoms First Approach
Show all chapter solutions
add
Ch. 12 - Consider an equilibrium mixture of four chemicals...Ch. 12 - The boxes shown below represent a set of initial...Ch. 12 - For the reactionH2(g)+I2(g)2HI(g), consider two...Ch. 12 - Given the reactionA(g)+B(g)C(g)+D(g), consider the...Ch. 12 - Consider the reaction A(g)+2B(g)C(g)+D(g) in a...Ch. 12 - Consider the reactionA(g)+B(g)C(g)+D(g). A friend...Ch. 12 - Consider the following statements: Consider the...Ch. 12 - Le Chteliers principle is stated (Section 12-7) as...Ch. 12 - The value of the equilibrium constant K depends on...Ch. 12 - Consider an initial mixture of N2 and H2 gases...Ch. 12 - Consider the following reaction:...Ch. 12 - Consider the same reaction as in Question 11. In...Ch. 12 - Suppose a reaction has the equilibrium constant K...Ch. 12 - Suppose a reaction has the equilibrium constant K...Ch. 12 - Consider the following reaction at some...Ch. 12 - Consider the following generic reaction:...Ch. 12 - Explain the difference between K, Kp, and Q.Ch. 12 - Consider the following reactions:...Ch. 12 - For a typical equilibrium problem, the value of K...Ch. 12 - Which of the following statements is(are) true?...Ch. 12 - Write the equilibrium expression (K) for each of...Ch. 12 - Write the equilibrium expression (Kp) for each...Ch. 12 - At a given temperature, K = 1.3 102 for the...Ch. 12 - For the reaction H2(g)+Br2(g)2HBr(g) Kp = 3.5 104...Ch. 12 - For the reaction 2NO(g)+2H2(g)N2(g)+2H2O(g) it is...Ch. 12 - At high temperatures, elemental nitrogen and...Ch. 12 - At a particular temperature, a 3.0-L flask...Ch. 12 - At a particular temperature a 2.00-L flask at...Ch. 12 - The following equilibrium pressures at a certain...Ch. 12 - The following equilibrium pressures were observed...Ch. 12 - At 327c, the equilibrium concentrations are...Ch. 12 - At 1100 K, Kp = 0.25 for the reaction...Ch. 12 - Write expressions for K and Kp for the following...Ch. 12 - Write expressions for Kp for the following...Ch. 12 - For which reactions in Exercise 33 is Kp equal to...Ch. 12 - For which reactions in Exercise 34 is Kp equal to...Ch. 12 - Consider the following reaction at a certain...Ch. 12 - In a study of the reaction...Ch. 12 - The equilibrium constant is 0.0900 at 25C for the...Ch. 12 - The equilibrium constant is 0.0900 at 25C for the...Ch. 12 - At 900c, Kp = 1.04 for the reaction...Ch. 12 - Ethyl acetate is synthesized in a nonreacting...Ch. 12 - For the reaction 2H2O(g)2H2(g)+O2(g) K = 2.4 103...Ch. 12 - The reaction 2NO(g)+Br2(g)2NOBr(g) has Kp = 109 at...Ch. 12 - A 1.00-L flask was filled with 2.00 moles of...Ch. 12 - A sample of S8(g) is placed in an otherwise empty...Ch. 12 - At a particular temperature, 12.0 moles of SO3 is...Ch. 12 - At a particular temperature, 8.0 moles of NO2 is...Ch. 12 - An initial mixture of nitrogen gas and hydrogen...Ch. 12 - Nitrogen gas (N2) reacts with hydrogen gas (H2) to...Ch. 12 - At a particular temperature, K = 3.75 for the...Ch. 12 - At a particular temperature, K = 1.00 102 for the...Ch. 12 - At 2200C, Kp = 0.050 for the reaction...Ch. 12 - At 25c, K = 0.090 for the reaction...Ch. 12 - At 1100 K, KP = 0.25 for the reaction...Ch. 12 - At a particular temperature, Kp = 0.25 for the...Ch. 12 - At 35C, K = 1.6 105 for the reaction...Ch. 12 - At o particular temperature, K = 4 .0 107 for the...Ch. 12 - At a particular temperature, K = 2.0 106 for the...Ch. 12 - Lexan is a plastic used to make compact discs,...Ch. 12 - At 25C, Kp. = 2.9 103 for the reaction...Ch. 12 - A sample of solid ammonium chloride was placed in...Ch. 12 - Suppose the reaction system...Ch. 12 - Predict the shift in the equilibrium position that...Ch. 12 - An important reaction in the commercial production...Ch. 12 - What will happen to the number of moles of SO3 in...Ch. 12 - In which direction will the position of the...Ch. 12 - Hydrogen for use in ammonia production is produced...Ch. 12 - Old-fashioned smelling salts consist of ammonium...Ch. 12 - Ammonia is produced by the Haber process, in which...Ch. 12 - Calculate a value for the equilibrium constant for...Ch. 12 - Given the following equilibrium constants at...Ch. 12 - Consider the decomposition of the compound C5H6O3...Ch. 12 - At 25C. Kp 1 1031 for the reaction a. Calculate...Ch. 12 - The gas arsine, AsH3, decomposes as follows:...Ch. 12 - At a certain temperature, K = 9.1 10-4 for the...Ch. 12 - At a certain temperature, K = 1.1 l03 for the...Ch. 12 - For the reaction PCl5(g)PCl3(g)+Cl2(g) at 600. K,...Ch. 12 - At 25C, gaseous SO2Cl2 decomposes to SO2(g) and...Ch. 12 - For the following reaction at a certain...Ch. 12 - Novelty devices for predicting rain contain...Ch. 12 - Consider the reaction Fe3+(aq)+SCN(aq)FeSCN2+(aq)...Ch. 12 - Chromium(VI) forms two different oxyanions, the...Ch. 12 - The synthesis of ammonia gas from nitrogen gas and...Ch. 12 - Suppose K = 4.5 103 at a certain temperature for...Ch. 12 - For the reaction below, Kp = 1.16 at 800C....Ch. 12 - Many sugars undergo a process called mutarotation,...Ch. 12 - Peptide decomposition is one of the key processes...Ch. 12 - The creation of shells by mollusk species is a...Ch. 12 - Methanol, a common laboratory solvent, poses a...Ch. 12 - For the reaction: 3O2(g)2O3(g) K = 1.8 107 at a...Ch. 12 - An equilibrium mixture contains 0.60 g solid...Ch. 12 - At a particular temperature, 8.1 moles of NO2 gas...Ch. 12 - A sample of solid ammonium chloride was placed in...Ch. 12 - In a given experiment, 5.2 moles of pure NOCl was...Ch. 12 - For the reactionN2O4(g)2NO2(g),Kp=0.25 at a...Ch. 12 - Consider the following exothermic reaction at...Ch. 12 - For the following endothermic reaction at...Ch. 12 - A 1.604-g sample of methane (CH4) gas and 6.400 g...Ch. 12 - A 4.72-g sample of methanol (CH3OH) was placed in...Ch. 12 - At 35C, K = 1.6 105 for the reaction...Ch. 12 - Nitric oxide and bromine at initial partial...Ch. 12 - At 25C. Kp = 5.3 105 for the reaction...Ch. 12 - Consider the reaction P4(g)2P2(g) where Kp = 1.00 ...Ch. 12 - The partial pressures of an equilibrium mixture of...Ch. 12 - At 125C, KP = 0.25 for the reaction...Ch. 12 - A mixture of N2, H2, and NH3 is at equilibrium...Ch. 12 - Consider the decomposition equilibrium for...Ch. 12 - An 8.00-g sample of SO3 was placed in an evacuated...Ch. 12 - A sample of iron(II) sulfate was heated in an...Ch. 12 - At 5000 K and 1.000 atm, 83.00% of the oxygen...Ch. 12 - A sample of N2O4(g) is placed in an empty cylinder...Ch. 12 - A sample of gaseous nitrosyl bromide (NOBr) was...Ch. 12 - The equilibrium constant Kp for the reaction...Ch. 12 - For the reaction NH3(g)+H2S(g)NH4HS(s) K = 400. at...Ch. 12 - Given K = 3.50 at 45C for the reaction...Ch. 12 - In a solution with carbon tetrachloride as the...Ch. 12 - The hydrocarbon naphthalene was frequently used in...Ch. 12 - A gaseous material XY(g) dissociates to some...

Additional Science Textbook Solutions

Find more solutions based on key concepts
Show solutions add
Which of the following describes the fat-soluble vitamins? a. few functions in the body b. easily absorbed and ...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

What is the monomer of a nucleic acid macromolecule?

Biology: The Dynamic Science (MindTap Course List)

A particle of mass m moves along a straight line with constant velocity v0 in the x direction, a distance b fro...

Physics for Scientists and Engineers, Technology Update (No access codes included)

Technically, there are no salts in seawater. How can that be?

Oceanography: An Invitation To Marine Science, Loose-leaf Versin