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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A spring oriented vertically is attached to a hard horizontal surface as in Figure P13.2. The spring has a force constant of 1.46 kN/m. How much is the spring compressed when a object of mass m = 2.30 kg is placed on top of the spring and the system is at rest?

images

Figure P13.2

To determine
To determine the compression of the spring.

Explanation

Given Info: The force constant of the spring is 1.46kNm-1 . The mass of the spring m is 2.30kg .

Since the mass m is placed on top of the spring, acceleration due to gravity will work on it. So, acceleration a is equal to g.

From Hooke’s law, the formula for the force is,

F=kx (I)

  • F is the force
  • k is force constant of the spring
  • x is the displacement of the spring

The force is equal to the force of gravity.

F=mg (II)

  • m is the mass of the object
  • g is the acceleration due to gravity

From Equations (I) and (II),

kx=mgx=mgk

Substitute 1.46kNm-1 for k , 2

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