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ChemistryIntroductory Chemistry: A Foundation9th Edition

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Chapter 15, Problem 69QAP
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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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69. What volume of 0.502 M NaOH solution would be required to neutralize 27.2 mL of 0.491 M HNO3 solution?

Interpretation Introduction

Interpretation:

The volume of 0.502 M

NaOH solution required to neutralize the given HNO3 solution is to be calculated.

Concept Introduction:

A chemical reaction that occurs between acid and base is known as neutralization reaction. An addition of the base into an acid results in the neutralization of an acid. During neutralization reaction, water is produced as a side product.

Explanation

The value of M1,  M2 and V1 is given to be 0.491 M, 0.502 M and 27.2 mL respectively.

The relationship between concentration and volume of both solutions is shown below.

M1V1=M2V2

Where,

  • M1 is the concentration of HNO3 solution.
  • V1 is the volume of HNO3 solution.
  • M2 is the concentration of NaOH solution.
  • V2 is the volume of NaOH solution.

Rearrange an above expression to calculate V2 which is needed to neutralize the HNO3 solution

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Sect-15.3 P-15.1SCSect-15.3 P-15.2SCSect-15.4 P-15.3SCSect-15.4 P-15.4SCSect-15.4 P-15.5SCSect-15.4 P-15.6SCSect-15.5 P-15.7SCSect-15.6 P-1CTSect-15.6 P-15.8SCSect-15.7 P-15.9SC
Sect-15.8 P-15.10SCSect-15.8 P-15.11SCCh-15 P-1ALQCh-15 P-2ALQCh-15 P-3ALQCh-15 P-4ALQCh-15 P-5ALQCh-15 P-6ALQCh-15 P-7ALQCh-15 P-8ALQCh-15 P-9ALQCh-15 P-10ALQCh-15 P-11ALQCh-15 P-12ALQCh-15 P-13ALQCh-15 P-14ALQCh-15 P-1QAPCh-15 P-2QAPCh-15 P-3QAPCh-15 P-4QAPCh-15 P-5QAPCh-15 P-6QAPCh-15 P-7QAPCh-15 P-8QAPCh-15 P-9QAPCh-15 P-10QAPCh-15 P-11QAPCh-15 P-12QAPCh-15 P-13QAPCh-15 P-14QAPCh-15 P-15QAPCh-15 P-16QAPCh-15 P-17QAPCh-15 P-18QAPCh-15 P-19QAPCh-15 P-20QAPCh-15 P-21QAPCh-15 P-22QAPCh-15 P-23QAPCh-15 P-24QAPCh-15 P-25QAPCh-15 P-26QAPCh-15 P-27QAPCh-15 P-28QAPCh-15 P-29QAPCh-15 P-30QAPCh-15 P-31QAPCh-15 P-32QAPCh-15 P-33QAPCh-15 P-34QAPCh-15 P-35QAPCh-15 P-36QAPCh-15 P-37QAPCh-15 P-38QAPCh-15 P-39QAPCh-15 P-40QAPCh-15 P-41QAPCh-15 P-42QAPCh-15 P-43QAPCh-15 P-44QAPCh-15 P-45QAPCh-15 P-46QAPCh-15 P-47QAPCh-15 P-48QAPCh-15 P-49QAPCh-15 P-50QAPCh-15 P-51QAPCh-15 P-52QAPCh-15 P-53QAPCh-15 P-54QAPCh-15 P-55QAPCh-15 P-56QAPCh-15 P-57QAPCh-15 P-58QAPCh-15 P-59QAPCh-15 P-60QAPCh-15 P-61QAPCh-15 P-62QAPCh-15 P-63QAPCh-15 P-64QAPCh-15 P-65QAPCh-15 P-66QAPCh-15 P-67QAPCh-15 P-68QAPCh-15 P-69QAPCh-15 P-70QAPCh-15 P-71QAPCh-15 P-72QAPCh-15 P-73QAPCh-15 P-74QAPCh-15 P-75QAPCh-15 P-76QAPCh-15 P-77QAPCh-15 P-78QAPCh-15 P-79QAPCh-15 P-80QAPCh-15 P-81QAPCh-15 P-82QAPCh-15 P-83QAPCh-15 P-84QAPCh-15 P-85QAPCh-15 P-86QAPCh-15 P-87QAPCh-15 P-88QAPCh-15 P-89APCh-15 P-90APCh-15 P-91APCh-15 P-92APCh-15 P-93APCh-15 P-94APCh-15 P-95APCh-15 P-96APCh-15 P-97APCh-15 P-98APCh-15 P-99APCh-15 P-100APCh-15 P-101APCh-15 P-102APCh-15 P-103APCh-15 P-104APCh-15 P-105APCh-15 P-106APCh-15 P-107APCh-15 P-108APCh-15 P-109APCh-15 P-110APCh-15 P-111APCh-15 P-112APCh-15 P-113APCh-15 P-114APCh-15 P-115APCh-15 P-116APCh-15 P-117APCh-15 P-118APCh-15 P-119APCh-15 P-120APCh-15 P-121APCh-15 P-122APCh-15 P-123APCh-15 P-124APCh-15 P-125APCh-15 P-126APCh-15 P-127APCh-15 P-128APCh-15 P-129APCh-15 P-130APCh-15 P-131APCh-15 P-132APCh-15 P-133APCh-15 P-134APCh-15 P-135APCh-15 P-136APCh-15 P-137CPCh-15 P-138CPCh-15 P-139CPCh-15 P-140CPCh-15 P-141CPCh-15 P-142CPCh-15 P-143CPCh-15 P-1CRCh-15 P-2CRCh-15 P-3CRCh-15 P-4CRCh-15 P-5CRCh-15 P-6CRCh-15 P-7CRCh-15 P-8CRCh-15 P-9CRCh-15 P-10CRCh-15 P-11CRCh-15 P-12CRCh-15 P-13CRCh-15 P-14CRCh-15 P-15CRCh-15 P-16CRCh-15 P-17CRCh-15 P-18CRCh-15 P-19CRCh-15 P-20CRCh-15 P-21CRCh-15 P-22CRCh-15 P-23CRCh-15 P-24CRCh-15 P-25CRCh-15 P-26CRCh-15 P-27CRCh-15 P-28CRCh-15 P-29CRCh-15 P-30CRCh-15 P-31CRCh-15 P-32CRCh-15 P-33CRCh-15 P-34CRCh-15 P-35CRCh-15 P-36CRCh-15 P-37CRCh-15 P-38CRCh-15 P-39CRCh-15 P-40CRCh-15 P-41CRCh-15 P-42CR

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