   Chapter 5, Problem 40PS

Chapter
Section
Textbook Problem

A piece of chromium metal with a mass of 24.26 g is heated in boiling water to 98.3 °C and then dropped into a coffee-cup calorimeter containing 82.3 g of water at 23.3 °C. When thermal equilibrium is reached, the final temperature is 25.6 °C. Calculate the specific heat capacity of chromium.

Interpretation Introduction

Interpretation:

The specific heat capacity of chromium has to be calculated.

Concept Introduction:

Heat energy required to raise the temperature of 1g of substance by 1K.Energy gained or lost can be calculated using the below equation.

q=C×m×ΔT

Where, q= energy gained or lost for a given mass of substance (m), C =specific heat

Capacity,ΔT= change in temperature.

Explanation

Assume qmetal=-qwater

24.26g×Cmetal(25.6-98.3)K=-[82.3g×4

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