   Chapter 5, Problem 73GQ

Chapter
Section
Textbook Problem

Use standard enthalpies of formation to calculate the enthalpy change that occurs when 1.00 g of SnCl4(ℓ) reacts with excess H2O(ℓ) to form SnO2(s) and HCl(aq).

Interpretation Introduction

Interpretation:

The enthalpy change of reaction has to be determined.

Concept Introduction:

The standard enthalpy of formation is the enthalpy change for the formation of 1mol of the compound directly from its component elements in their standard states.

Enthalpy change for the reaction ΔrH0=ΣnΔfH0(products)-ΣnΔfH0(reactants)

Explanation

Consider this equation.

SnCl4+2H2OSnO2+H2O

ΔfH0(SnCl4) =-545.2kJ/mol

ΔfH0(2H2O)=-571.6kJ/mol

ΔfH0(SnO2)=-580.7kJ/mol

ΔfH0(4HCl)=-369

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