# A potter’s wheel moves uniformly from rest to an angular velocity of 1.00 rev/s in 30.0 s. (a) Find its angular acceleration in radians per second per second, (b) Would doubling the angular acceleration during the given period have doubled final angular velocity?

### College Physics

11th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305952300

### College Physics

11th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305952300

#### Solutions

Chapter
Section
Chapter 7, Problem 4P
Textbook Problem

## A potter’s wheel moves uniformly from rest to an angular velocity of 1.00 rev/s in 30.0 s. (a) Find its angular acceleration in radians per second per second, (b) Would doubling the angular acceleration during the given period have doubled final angular velocity?

Expert Solution

(a)

To determine
The angular acceleration of the potter’s wheel.

### Explanation of Solution

Given info: The initial angular velocity of the wheel is 0rev/s , the final angular speed of the wheel is 1.00rev/s , and the time interval is 30.0s .

Explanation:

The formula for the angular acceleration of the wheel is,

α=ωfωiΔt

• ωi is the initial angular velocity of the potter’s wheel
• ωf is the final angular velocity of the potter’s wheel

Substitute 0rev/s for ωi , 1.00rev/s for ωf , and 30.0s for Δt to find α

Expert Solution

(b)

To determine
The doubling of the angular velocity during the constant period the angular acceleration is doubled.

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