   Chapter 9, Problem 53QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
106 views

# Lead(II) oxide from an ore can be reduced to elemental lead by heating in a furnace with carbon.:math> PbO ( s ) + C ( s ) → Pb ( l ) + CO ( g ) lculate the expected yield of lead if 50.0 kg of lead oxide is heated with 50.0 kg of carbon.

Interpretation Introduction

Interpretation:

The expected yield of lead if 50.0 kg of lead oxide is heated with 50.0 kg of carbon should be calculated.

Concept Introduction:

The expected or theoretical yield of the product depends on the limiting reactant of the reaction. Limiting reactant is the reactant that limits the mass of product formed in the reaction.

Explanation

The balanced chemical reaction is as follows:

PbO(s)+C(s)Pb(l)+CO(g)

To determine the limiting reactant, first calculate the number of moles of PbO and C as follows:

Mass of PbO is 50 kg and molar mass is 223.2 g/mol thus, number of moles will be:

n=mM

Putting the values,

n=50 kg(1000 g1 kg)223.2 g/mol=224.01 mol

From the balanced chemical reaction, 1 mol of PbO gives 1 mol of lead thus, 224.01 mol of PbO gives 224.01 mol of lead.

Molar mass of lead is 207.2 g/mol thus, mass will be:

m=n×M

Putting the values,

m=(224.01 mol)(207.2 g/mol)=46.42×103 g=46

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