4) Can this motion be modeled as a constant acceleration problem?
If so, what is the acceleration, and explain how you calculated it.
Yes the constant acceleration will be the slope of the graph since the rate at which velocity
changes with time is a constant rate, which means that acceleration can be calculated by subtracting the final velocity minus initiation and then dividing it by the change in
time. (16.8 m/s - 0 m/s)/ (10s - 0s)= 1.68 m/s^2
5) What does the R-squared represent?
R-square represents how closely the data fit the regression model. It is a statistical measure of how close the data is to the trendline. The closer the R-square value to the number 1 the closer the data is to the trendline.
6) Given that x(0) = 0 and v(0) = 0, we need only one other point to make a parabolic curve
of x(t) = At^2 + Bt + C. Use x(10) = 83.5 for that third point. Determine A, B, and C.
How do these coefficients relate to the physical parameters?
x(t)= At^2 + Bt +C
v(t)= x’(t)= 2At + B
x(0)= A0^2 + B0 + C= 0
x(0)= C = 0
v(0)= 2 A(0) + B = 0
v(0)= B = 0
x(10)= A (10)^2 = 83.5
A= 83.5/100 A= 0.835
A represents half the acceleration, which is constant. B represents the initial velocity and C
represents the initial position.