Lab 4- Column Chromatography and Redox Biochemistry
.docx
keyboard_arrow_up
School
Concordia University *
*We aren’t endorsed by this school
Course
271,221
Subject
Chemistry
Date
May 27, 2024
Type
docx
Pages
6
Uploaded by MegaSnailMaster1165
Results Part 1: Column Chromatography Table 1. Color of the fractions obtained in Column Chromatography of LDH, Cytochrome C and FMN, and LDH assay results for the clear fractions at 340nm. Fraction
Color
Rate (Abs/min)
at 340 nm
LDH activity
(μmol/min)
% LDH activity
#1
Clear 0.04275708
0.007245
5.67%
#2
Clear -0.1442514
0.02444
19.1%
#3
Clear
-0.7537793
0.1277
100%
#4
Clear
-0.1865322
0.03161
24.8%
#5
Light orange -0.02583046
0.004377
3.43%
#6
Light orange -
-
-
#7
Orange
-
-
-
#8
Brownish orange
-
-
-
#9
Light orange -
-
-
#10
Light yellow -
-
-
#11
Light yellow -
-
-
#12
Yellow -
-
-
#13
Bright yellow -
-
-
#14
Yellow -
-
-
#15
Light yellow -
-
-
Part : Reduction using Ascorbate Table 2. Reduction of Cytochrome C and FMN with ascorbate (vitamin C) monitored at the respective wavelengths of 550 nm and 450 nm.
Protein
Fraction
Color
Wavelength
Absorbance
before Ascorbate
Absorbance
after Ascorbate
Flavin
Mononucleotide
(FMN)
#13
Bright
Yellow
450 nm
2.0236
1.9819
Cytochrome C
#8
Reddish
Brown
550 nm
1.0690
1.5765
Calculations
Fraction #1: A = ε x L x C ∆C(mol/min) = ∆A/(ε x L)
∆C(mol/min) = 0.04275708/(6250 x 1) = 6.841 x 10
-6 mol/min
NADH (mol/min) = ∆C x Tv
= (6.841 x 10
-6
) x (1.059 x 10
-3
) = 7.245 x 10
-9 mol/min Enzyme activity =0.007245 μmol/min
%LDH activity = (0.007245 μmol/min / 0.1277 μmol/min) x 100% = 5.67 %
Fraction #2: A = ε x L x C ∆C(mol/min) = ∆A/(ε x L)
∆C(mol/min) = 0.1442514/(6250 x 1) = 2.308 x 10
-5 mol/min
NADH (mol/min) = ∆C x Tv
= (2.308 x 10
-5
) x (1.059 x 10
-3
) = 2.444 x 10
-8 mol/min Enzyme activity =0.02444 μmol/min
%LDH activity = (0.02444 μmol/min / 0.1277 μmol/min) x 100% = 19.1%
Fraction #3: A = ε x L x C ∆C(mol/min) = ∆A/(ε x L)
∆C(mol/min) = 0.7537793/(6250 x 1) = 1.206 x 10
-4 mol/min
NADH (mol/min) = ∆C x Tv
= (1.206 x 10
-4
) x (1.059 x 10
-3
) = 1.277 x 10
-7 mol/min Enzyme activity =0.1277 μmol/min
%LDH activity = 100% because the highest enzyme activity.
Fraction #4: A = ε x L x C ∆C(mol/min) = ∆A/(ε x L)
∆C(mol/min) = 0.1865322/(6250 x 1) = 2.985 x 10
-5 mol/min
NADH (mol/min) = ∆C x Tv
= (2.985 x 10
-5
) x (1.059 x 10
-3
) = 3.161 x 10
-8 mol/min Enzyme activity =0.03161 μmol/min
%LDH activity = (0.03161 μmol/min / 0.1277 μmol/min) x 100% = 24.8%
Fraction #5: Column Chromatography and Redox Biochemistry .
2
A = ε x L x C ∆C(mol/min) = ∆A/(ε x L)
∆C(mol/min) = 0.02583046/(6250 x 1) = 4.132 x 10
-6 mol/min
NADH (mol/min) = ∆C x Tv
= (6.841 x 10
-6
) x (1.059 x 10
-3
) = 4.377 x 10
-9 mol/min Enzyme activity =0.004377 μmol/min
%LDH activity = (0.004377 μmol/min / 0.1277 μmol/min) x 100% = 3.43% Post-Lab Questions Part 1: 1.
In what order did you expect FMN, LDH and Cytochrome C to elute from the column. Explain Why.
Gel-Filtration chromatography is conducted to separate the species of proteins or
molecules present in the solution according to their size. The column is packed with resin
Bio Gel P-200 which contains fine porous beads made of an insoluble polymer.
Therefore, the small molecules are capable of entering these porous beads and therefore
spend a lot more time in the resin, whereas the larger molecules in the fractionation range
of 30-200 kDa, are able to pass through the resin relatively quickly. Thus, this technique
allows the large molecules to pass through the column quickly and be the first to elute
form the column, whereas the small ones remain in the column chromatography elute the
last, since they are in the porous beads longer and travel slower. The Sample mixture provided contained LDH, Cytochrome C and FMN. It was
expected that LDH would be the first to elute from the column since it is the largest
protein, with a molecular size of 140 kDa and is composed of around 322 residue amino
acids. Cytochrome C would be the second and FMN would be the last to emerge out of
the column because of their respective sizes of 12kDa and 0.46kDa. 2.
Did these three molecules elute in the expected order? If not, suggest a reason why?
The three molecules indeed elute in the expected order, with LDH being concentrated in
fraction #3, Cytochrome C in fraction #8 and FMN in fraction #13. It was also easy to
distinguish the order for cytochrome C and FMN since they are colored reddish brown
and yellow respectively. The fractions with the brightest colors were assumed to be the
ones with the species being most concentrated in. For LDH, since it is colorless, multiple
LDH assays were conducted on the clear fractions and LDH activity was found to be the
highest in the fraction #3. 3.
What was the purpose of assaying LDH activity in the column fractions?
The purpose of assaying LDH activity in the column fractions was to determine which of
the fractions had LDH concentrated. And since LDH is colorless, it was difficult to
determine its presence in a fraction with naked eye. It was expected that LDH would be
the first to be separated since it is the largest protein out of the three, therefore assaying
Column Chromatography and Redox Biochemistry .
3
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Questions
Column Chromatography
Alumina
Chromatography Mixture
9:1 Hexanes:Ether
8:2 Hexanes:Ether
1:1 Hexanes:Acetone
Amount Used
3.962 g
0.143 g
9.50 mL
9.50 mL
11.00 mL
Additional Observations (Color, etc.)
BIU X₂ X² →
BI IU X₂ X² →
BI IU X₂ X² →
BI IU X₂ X² →
BIU X₂ X² →
arrow_forward
Qno1: why there is a need of chromatography and chromatography thecniqs. B) when and where we should use normal and reverse phase chromatography
arrow_forward
Which one of the following chromatographic
techniques is useful in the identification of
organic molecules having molecular weights
more than 20,000?
1) reverse phase chromatography
2) normal phase chromatography
3) high pressure liquid chromatography
4) gel permeation chromatography
arrow_forward
Answer sections C, D and E in the same answer book.
Section D (Chromatography)
Question 8
The following data were obtained for the analysis of a mixture of compounds (A-D) by
HPLC:
Peak
Retention time (min) | Width of peak base (min)
non-retained
2.1
A
6.4
10.51
B
11.3
1.03
C
13.1
1.25
D
21.6
1.62
a) Using peak C. calculate the number of plates (N) in this column.
b) For peak D, calculate the capacity factor (k').
c) For peak B and C, calculate the resolution (R).
arrow_forward
Use a suitable model to explain how separation and identification of a mixture of organic compounds can be achieved with a thin layer chromatographic (TLC) technique.
arrow_forward
use the following chromatogram and table as your data.
What is the %composition of the Vitamin A peak in the sample?
78.43%
77.73%
7.867%
72.74%
arrow_forward
two chromatograms after LC separation. Which chromatogram is better to proceed for MS analysis? What mobile phase condition/composition (LC separation) was used?
arrow_forward
In molecular exclusion (size exclusion)
chromatography, the molecules have the
longest retention times.
a) the larger molecules
b) the smaller molecules
arrow_forward
Based on the given chromatograph, answer the following questions:1) Which of the diet sodas have the highest concentration of caffeine? Which standard best reflects this concentration?2) Which of the diet sodas have the lowest concentration of aspartame? Which standard best reflects this concentration?3) What is the approximate retention time of benzoate?
arrow_forward
4) If the classification of the chromatography run is a reverse-phase chromatography, discuss the relative polarities of caffeine, aspartame and benzoate
arrow_forward
Question 7
The relative peak areas and retention for a mixture of five fatty acids separated by GC is given in the table shown below. Based on this information,
what percentage of the total content is comprised of FA 3?
Retention time
Peak Area
Fatty Acid
1
4.176
123314
2
6.004
35669
3
7.542
78968
4
9.256
16122
5
13.196
28074
OA. 43.7%
O B. 30.0%
O C. 47.3%
O D. 33.7%
arrow_forward
Three students did a chromatography experiment, where Rf = distance of solute / distance of solvent.
What could be the possible errors why student 3 had results that are quite far from that of students A and B?
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
EBK A SMALL SCALE APPROACH TO ORGANIC L
Chemistry
ISBN:9781305446021
Author:Lampman
Publisher:CENGAGE LEARNING - CONSIGNMENT
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Related Questions
- Column Chromatography Alumina Chromatography Mixture 9:1 Hexanes:Ether 8:2 Hexanes:Ether 1:1 Hexanes:Acetone Amount Used 3.962 g 0.143 g 9.50 mL 9.50 mL 11.00 mL Additional Observations (Color, etc.) BIU X₂ X² → BI IU X₂ X² → BI IU X₂ X² → BI IU X₂ X² → BIU X₂ X² →arrow_forwardQno1: why there is a need of chromatography and chromatography thecniqs. B) when and where we should use normal and reverse phase chromatographyarrow_forwardWhich one of the following chromatographic techniques is useful in the identification of organic molecules having molecular weights more than 20,000? 1) reverse phase chromatography 2) normal phase chromatography 3) high pressure liquid chromatography 4) gel permeation chromatographyarrow_forward
- Answer sections C, D and E in the same answer book. Section D (Chromatography) Question 8 The following data were obtained for the analysis of a mixture of compounds (A-D) by HPLC: Peak Retention time (min) | Width of peak base (min) non-retained 2.1 A 6.4 10.51 B 11.3 1.03 C 13.1 1.25 D 21.6 1.62 a) Using peak C. calculate the number of plates (N) in this column. b) For peak D, calculate the capacity factor (k'). c) For peak B and C, calculate the resolution (R).arrow_forwardUse a suitable model to explain how separation and identification of a mixture of organic compounds can be achieved with a thin layer chromatographic (TLC) technique.arrow_forwarduse the following chromatogram and table as your data. What is the %composition of the Vitamin A peak in the sample? 78.43% 77.73% 7.867% 72.74%arrow_forward
- two chromatograms after LC separation. Which chromatogram is better to proceed for MS analysis? What mobile phase condition/composition (LC separation) was used?arrow_forwardIn molecular exclusion (size exclusion) chromatography, the molecules have the longest retention times. a) the larger molecules b) the smaller moleculesarrow_forwardBased on the given chromatograph, answer the following questions:1) Which of the diet sodas have the highest concentration of caffeine? Which standard best reflects this concentration?2) Which of the diet sodas have the lowest concentration of aspartame? Which standard best reflects this concentration?3) What is the approximate retention time of benzoate?arrow_forward
- 4) If the classification of the chromatography run is a reverse-phase chromatography, discuss the relative polarities of caffeine, aspartame and benzoatearrow_forwardQuestion 7 The relative peak areas and retention for a mixture of five fatty acids separated by GC is given in the table shown below. Based on this information, what percentage of the total content is comprised of FA 3? Retention time Peak Area Fatty Acid 1 4.176 123314 2 6.004 35669 3 7.542 78968 4 9.256 16122 5 13.196 28074 OA. 43.7% O B. 30.0% O C. 47.3% O D. 33.7%arrow_forwardThree students did a chromatography experiment, where Rf = distance of solute / distance of solvent. What could be the possible errors why student 3 had results that are quite far from that of students A and B?arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- EBK A SMALL SCALE APPROACH TO ORGANIC LChemistryISBN:9781305446021Author:LampmanPublisher:CENGAGE LEARNING - CONSIGNMENT
- Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
EBK A SMALL SCALE APPROACH TO ORGANIC L
Chemistry
ISBN:9781305446021
Author:Lampman
Publisher:CENGAGE LEARNING - CONSIGNMENT
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning