6-1 Ideal Gas Law Constant Lab Report

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Southern New Hampshire University *

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Chemistry

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Oct 30, 2023

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Determination of Ideal Gas Law Constant S tudent: Ashley Shaw Date: 06/10/23 Activity 1 If your concentration, moles, or R calculations are incorrect or your calculation work does not actually result in the desired final units, or units are missing/incomplete, or cancelled incorrectly, you will lose points. Be sure that every number you include has its associated unit. Email me if you are unsure or need assistance. Data Table 1 Trial 1 (1 mL H 2 O 2 ) Trial 2 (1 mL H 2 O 2 ) Trial 3 (2 mL H 2 O 2 ) Trial 4 (2 mL H 2 O 2 ) Trial 5 (3 mL H 2 O 2 ) Trial 6 (3 mL H 2 O 2 ) Trial 7 (4 mL H 2 O 2 ) Trial 8 (4 mL H 2 O 2 ) Air temperature (°C) 23 °C 23 °C 23 °C 23 °C 23 °C 23 °C 23 °C 23 °C Volume H 2 O 2 liquid (mL) 1mL 1mL 2mL 2mL 2mL 2mL 4mL 4mL Initial Volume Gas (mL) 2mL 4mL 5mL 1mL 8mL 3mL 4mL 2mL Final Volume Gas (mL) 8mL 12mL 23mL 20mL 36mL 32mL 42mL 42mL ΔV (mL) 6mL 8mL 18mL 19mL 28mL 29mL 38mL 40mL ©2016 2 Carolina Biological Supply Company
2021 Activity 2 Data Table 2 Show work for determining Concentration of H 2 O 2 in the box below. Concentration should be mol/L. You need to begin your calculation using the provided 3%m/v H 2 O 2 concentration . Concentration H 2 O 2 (mol/L) 3g/mL H 2 O 2 = 30g/L H 2 O 2 Change to grams per liter 30 g / L 34.01 g / mol = 0.8 mol/L (grams cancels and your left with mol/L) Trial 1 1 mL H 2 O 2 Trial 2 1 mL H 2 O 2 Trial 3 2 mL H 2 O 2 Trial 4 2 mL H 2 O 2 Trial 5 3 mL H 2 O 2 Trial 6 3 mL H 2 O 2 Trial 7 4 mL H 2 O 2 Trial 8 4 mL H 2 O 2 Moles H 2 O 2 0.0008 mol 0.0008 mol 0.0016 mol 0.0016 mol 0.0024 mol 0.0024 mol 0.0032 mol 0.0032 mol Moles O 2 * 0.0004 mol 0.0004 mol 0.0008 mol 0.0008 mol 0.0012 mol 0.0012 mol 0.0016 mol 0.0016 mol ΔV (L) 6mL / 1000 0.006 L 8mL / 1000 0.008 L 8mL / 1000 0.018 L 19mL / 1000 0.019 L 28mL / 1000 0.028 L 29mL / 1000 0.029 L 38mL / 1000 0.038 L 40mL / 1000 0.040 L *Hint: Use reaction stoichiometry/molar ratio to solve for moles of O 2 . Show work for determining moles of H 2 O 2 for Trial 1 here: 1ml / 1000 = 0.001 L H 2 O 2 0.001 L H 2 O 2 x 0.8 mol/L= 0.0008 mol H 2 O 2 Show work for determining moles of O 2 for Trial 1 here: 2 H 2 O 2 2 H 2 O + O 2 2 H 2 O 2 : 1 O 2 0.0008 mol H 2 O 2 / 2 = 0.0004 mol O 2 Show work for determining moles of H 2 O 2 for Trial 3 here: 2ml / 1000 = 0.002 L H 2 O 2 0.002 L H 2 O 2 x 0.8 mol/L= 0.0016 mol H 2 O 2 Show work for determining moles of O 2 for Trial 3 here: 2 H 2 O 2 2 H 2 O + O 2 2 H 2 O 2 : 1 O 2 0.0016 mol H 2 O 2 / 2 = 0.0008 mol O 2 Show work for determining moles of H 2 O 2 for Trial 5 here: 3ml / 1000 = 0.003 L H 2 O 2 0.003 L H 2 O 2 x 0.8 mol/L= 0.0024 mol H 2 O 2 Show work for determining moles of O 2 for Trial 5 here: 2 H 2 O 2 2 H 2 O + O 2 2 H 2 O 2 : 1 O 2 0.0024 mol H 2 O 2 / 2 = 0.0012 mol O 2 Show work for determining moles of H 2 O 2 for Trial 7 here: © 2016 Carolina Biological Supply Company
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