Lab Report 5_CH 237-016
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Patti Smith
CH 237-016
TA: Deblina Bhowmick
3/2/23
Experiment 5: Thin Layer Chromatography Analysis of Drug Compounds
I. Introduction
This lab addresses the composition of various unknown analgesic drugs. There are four
standard components to this type of mixture: aspirin, acetaminophen, ibuprofen, and caffeine.
Each of these compounds contain unique properties that can provide information about
unknown compounds when compared side by side. Through these comparisons, three unknown
drugs will be identified per the goal of this experiment. According to the literature, the
unknowns may be as follows: Advil (200mg Ibuprofen), Anacin (400mg Aspirin, 32mg Caffeine),
Aspirin (325mg Aspirin), Excedrin (250mg Aspirin, 250mg Acetaminophen, 65mg Caffeine), or
Tylenol (325mg Acetaminophen).
In order to compare the standards to the unknowns and determine which drugs are
being tested, a variety of techniques are used. A small spot of each solution (three unknowns
and the four standards) is added in its own section to the starting line of a silica gel thin layer
chromatography (TLC) plate with a fluorescent indicator. The TLC plate is developed in 200:1
ethylacetate/acetic acid and then allowed to dry. Once dry, short-wavelength (254nm) UV light
is used to identify the centers of intensity for each spot. These intensity centers are compared
so as to identify each component. Each standard shows a unique spot placement on and the
unknowns reflect this with their component(s).
II. Results
R
f
(aspirin): 2.4cm/2.9cm =
0.83
R
f
(acetaminophen): 1.7cm/2.9cm =
0.59
R
f
(ibuprofen): 2.6cm/2.9cm =
0.90
R
f
(caffeine): 0.6cm/2.9cm =
0.21
R
f
(unknown 1)
1
st
spot: 0.5cm/2.9cm =
0.17
2
nd
spot: 2.1cm/2.9cm =
0.72
R
f
(unknown 2)
1
st
spot: 0.6cm/2.9cm =
0.21
2
nd
spot: 1.7cm/2.9cm =
0.59
3
rd
spot: 2.1cm/2.9cm =
0.72
R
f
(unknown 3): 2.5cm/2.9cm =
0.86
III. Discussion
A TLC was run in order to identify the presence of various standard active ingredients in
three unknown samples. Comparisons are made between the unknowns and standards through
the calculated R
f
values.
The R
f
values and molecular structures communicate a great deal
about each standard. It can be assumed that of the four standards caffeine is by far the most
polar, followed by acetaminophen, aspirin, and ibuprofen. Compounds that are highly polar are
highly retained in the TLC which is shown by a low R
f
value, such as that of caffeine (0.21). The
molecular structure of caffeine contains a good amount of both nitrogen atoms and carboxylate
groups, which are more polar than carbon and pull electrons closer through lone pairs. Caffeine
is also bicyclic, which can increase polarity.
Acetaminophen and aspirin contain a similar number of polar atoms to each other, but
less than caffeine, which could explain some of the similarities and differences in polarity. The
differences mainly come in the presence of a benzene ring in acetaminophen and aspirin, while
there is not one present in caffeine. The lone pairs of nitrogen and electronegative hydroxyl and
carbonyl groups of acetaminophen make it more polar than the ester of aspirin. Ibuprofen is
much less polar than any of the other standards because it lacks multiple polar functional
groups.
The observed R
f
values for the unknown components are not exactly the same as the
standards, but they are comparable enough to infer. For example, the first spot of unknown 1
had an R
f
value of 0.17 which is slightly lower than the caffeine standard (0.21). However, these
two values are close enough to each other that it can be assumed that the unknown is caffeine.
The discrepancies between the two values are likely due to some spots overlapping during the
spotting process as some spots were larger than desired. Overlaps could cause the TLC to
appear as if other compounds were in a row that they were not or slightly affect the solutions
polarity. Both could result in the TLC being less accurate. Other than the possibility of initial
overlap, there were not many noticeable errors as the solvent did not reach the start line and
wash away any spots.
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Related Questions
PART ONE: Preparation of FECNS* Solution
Prepare the two solutions in table 1 by accurately measuring the required volumes of distilled
water and CNS into two labeled test tubes. The absorbance of the solutions must be measured
soon after adding the Fe" solution from a buret.
TABLE 1
Fe
5 ml
5S mL
Solution
Distilled Water
CNS
2 mL
Total Volume
3 ml
2 ml
10 ml
3 mL
10 ml
In this part of the experiment you are to explore what the above quote means. As a
PRELIMINARY Exercise, formulate a hypothesis as to what would happen under each of the
following circumstances:
1. 1ml of 0.0020 M CNS' solution is added to the unused portion of
solution 1 in the test tube
2. One drop of 0.20 M CNS solution is added to the unused portion of
solution 2 in the test tube.
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sulfur or nitrogen
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halogenated compounds
flame ionization
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mass spectrometer
nitrogen and phosphorous
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thermal conductivity
electrolytic conductivity
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electron capture
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use the following chromatogram and table as your data.
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78.43%
77.73%
7.867%
72.74%
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Thin-layer chromatography (TLC)
Gas chromatography (GC)
Liquid chromatography (LC) (i.e, high performance liquid chromatography or HPLC)
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D. Solvent Extraction
Samples
Upper phase
Lower phase
Oil + Water
Kerosene + Oil
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4
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An oil sample had its iodine number determined using the pyridinium tribromide
method. The sample and reagents used are as follows:
Oil sample: 0.19 mL, density: 0.954 g/mL
Pyridinium tribromide: 0.472 g
Na2S203: 0.1 M, endpoint 27.68 mL
%3D
What is the approximate Bromine Number?
O 138
89
O 120
O 200
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Consider the following molecules. Which statement(s) is TRUE?
CH3
CH3
но
ČH3
но
ČD3
i. You could differentiate between the two with a spot test.
ii. You could differentiate between the two with liquid chromatography.
iii. You could differentiate between the two with TLC.
iv. You could differentiate between the two with a microcrystalline test.
O a. i and iv only
O b. ii and iii only
O c. iii only
O d. i only
e. Neither i, ii, iii, nor iv are correct statements.
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PLEASE Answer within 20-30 minutes. Thank you!
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A student performed a chromatography
experiment to determine the Rf value of an
unknown amino acid. The distances traveled by
the amino acid and the solvent line were 3.0 cm
and 8.5 cm, respectively. What is the Rf value for
this amino acid?
0.3 cm
O 0.35
1.8
5.5
0.85 cm
0.65
O 2.8
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BSA stock solution. To these dilutions, 100 µl of Bradford reagent were added. After 5 minutes, the absorbance was taken at 595 nm.
Standard #
BSA,
in mg/mL
Volume of Bradford reagent, A595
in mL
1
5.0
0.000
1.00
5.0
0.134
3
2.00
5.0
0.265
4
3.00
5.0
0.388
4.00
5.0
0.497
The supernatant dilution was prepared by mixing 49 µL of the protein isolate with 16 µL water. The absorbance was taken 5 minutes after addition of 100 mL Bradford
reagent. Calculate the protein concentration (in mg/mL) of the original isolate if the absorbance at 595 nm was 0.413.
Note: Final answer format must be x.xxx (three decimal places). Round off only in the final answer. Do not round off in the middle of calculation.
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The spectroscopic data in the table is generated with five solutions of known concentration.
Concentration (M)
0.0133
m=
0.0266
0.0532
0.106
0.213
Absorbance
0.1271
What is the intercept of the linear regression line?
0.08531
0.5388
1.069
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1.954
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M-1
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Octane (C8H18, boiling point: 126 ºC) is eluted later than dodecane (C12H26, boiling point: 216 ºC)
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shown below: Cuvette 1 is the clank
Cuvette #
ml albumin
Absorbance
0.
0.2
.063
3
0.4
.163
4.
0.6
.187
0.8
.253
1.0
.289
Using this data, plot an Excel graph showing absorbance (y-axis) vs ml albumin (x-axis). Find the
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fair data. How would you describe this data?-
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(Lowry) x 200 ml (Lowry)/100 mL (Biuret). This implifies to Relative sensitivity = 20 dilution
factor x absorbance (Lowry)/Absorbance (Biuret). Report your relative sensitivity as an average
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The measured signal from the analysis of each 50 mL sample (on y axis) produced a straight line with the general equation:
y = 44.72x + 4.06
what was the final concentration of Z in the 50 mL standard addition sample? what was the initial concentration of Z in the original urine sample?
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None of these answers are correct.
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To generate IUPAC names for hydrocarbons.
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anch of the following components cannot be detected by gas chromatography?
4 Essential oils
Alcohols
b) Volatile compounds
d) Non-volatile compounds
13-
is measured as time elapsed from the point of injection to the peak maximum?
a)-Column efficiency d)- Delectability
c)-Retention time
14- Which of the following can be used to detect the components in gas chromatography
a) non-volatile compounds b) volatile compounds
c) Salts
d) b&c
15-Which of the following methods is often referred to as mechanical separation processes.
a)-Gas Chromatography b)-column chromatography c)- Sedimentation
16- For obtaining better resolution in TLC.
and then developed with a second solvent at right angles to the first
a) Stepwise b) Descending e) Ascending
17- This is defined as transport of electrically charged particles in a direct-current electric field
a) ion exchange chromatography b) Electrophoresis c) ultracentrifuge
d) exclusion
18-This figure indicates to schematic Diagram of
a) Gas chromatography…
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Table 2: Absorbance Values of Standards and Unknowns.
Sample
Blank
Standard Solution 1
Standard Solution 2
Standard Solution 3
Standard Solution 4
Standard Solution 5
Water Sample 1
Water Sample 2
Phosphate Concentration
(in ppm)
Y17
0 ppm
0.02 ppm
0.04 ppm
0.08 ppm
0.16 ppm
0.32 ppm
Freeman Lake
0.001
0.325
0.292
0.413
0.315
0.039
0.054
0.049
Absorbance at
2= 690 nm
Calculations:
1. Construct a phosphate standard curve in Excel by plotting concentration (in ppm) on your
x-axis and Absorbance (unitless) on your y-axis for your known solutions. Label the axes
on the graph and provide the curve with a title. Use a linear trendline to generate a best fit
line to your data. Label the graph with the equation and the R" value. Insert your labeled
graph in the space below.
X
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normal calibration curve. Standard solutions of caffeine were prepared and analyzed
using a 10-µL fixed-volume injection loop. Results for the standards are summarized
in the following table.
Concentration of Standards
Signal
(arbitrary units)
(ppm)
50.0
8354
100.0
16925
150.0
25218
200.0
33584
250.0
42002
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adding 10 mL of methanol. After allowing the sample to dissolve, the contents of the
beaker, including the insoluble binder, were quantitatively transferred to a 25-mL
volumetric flask and diluted to volume with methanol. The sample was then filtered,
and a 1.00-mL aliquot was transferred to a 10-mL volumetric flask and diluted to
volume with methanol. When analyzed by HPLC, the signal for the caffeine was
found to be 21469. Report the number of milligrams of caffeine in the analgesic
tablet.
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Color BEFORE adding
Color AFTER adding
Intensity of color AFTER
adding FeCl3
Test Tube #
FeCl3
FeCl3
#1 (salicylic acid)
clear
lilac
100%
#2 (commercial aspirin A) clear
slightly pink
50%
#3 (commercial aspirin B) clear
lilac
95%
#4 (aspirin from your
clear
pink
20%
synthesis above)
#5 (control)
clear
clear
0%
Based on this data and the melting point of Aspirin, how pure is the synthesized product?
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42.9%, 57.1%, or 52.8%
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detector first
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not know what analytes are in the sample we use
than scan.
▪ A) Scan; SIM
■ B)SIM; scan
• C) SIM; SIM
mode. When we do
mode. SIM allows greater sensitivity
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