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Questions:
Part 1: Use of Micropipettes
1.
Test Tube 1
0.2587 A.U. Test Tube 2
0.2787 A.U.
Test Tube 3
0.2683 A.U.
Absorbance values of p-nitrophenol and glycine buffer at 410nm of cuvette prepared with three tubes of the same concentrations to test pipetting competency. 2.
0.2ml p-nitrophenol (Test tube 1)
0.5116 A.U.
0.2ml p-nitrophenol (Test tube 2)
0.5417 A.U.
0.4ml p-nitrophenol (Test tube 3)
1.0238 A.U.
0.6ml p-nitrophenol (Test tube 4)
1.3954 A.U.
Absorbance values of increasing volumes of p-nitrophenol and glycine buffer were recorded by a
spectrometer at 410nm and zeroed with water as a reference. There is a proportional increasing positive relationship between the amount of p-
nitrophenol added and the absorbance. The increase is not exactly linear as the average of the first tubes (0.2 ml of p-nitrophenol) is 0.5267 which would give the expected linear amount of tube #3 to be 1.0533, but this value is not far away from the absorbance value obtained of 1.0238. Tube #4 is expected to have an absorbance if directly proportional to 1.5801, but the obtained value from the experiment is lower. These values should be directly proportional though due to the assumption in The Beer-Lambert law. In this law, absorbance should be directly proportional to the concentration as the amount of light intensity projected at the cuvette is measured to see the amount of intensity lost on the other side of the cuvette (Clark, 2016). The
amount of intensity lost in this process is the absorption by the sample, which should increase with the increasing amount of concentration as more molecules interact with the light (Clark,
2016). These lower amounts could be due to only completing one trial for the 0.4ml and 0.6ml of p-nitrophenol or improper pipette techniques resulting in lower concentrations. 3.
Test tubes 1 and 2 do not have the same numbers, but the two numbers fall within a similar range. They should have the same value as both received the same amount of p-
nitrophenol in the test tubes. Although test tube 1 and test tube 2 used two different micropipettes with differing ranges, both are able to achieve a similar absorbance value result as both allocated the same amount of solution. Part 2 Kinetics of hydrolysis of p-nitrophenylacetate
1.
Calculations to find the dilutions were found using the formula M
1
V
1
=M
2
V
2 and it was rearranged to V
1
=(M
2
V
2
)/M
1
This was used to find the Test tube 1 by inserting the known value
M
2
-0.05mM
V
2
-5 ml
M
1
-10mM
V
1
=(5ml x 0.05mM)/ 10mM =0.025ml of stock solution of 10mM p-nitrophenylacetate and 4.975ml of water
It is possible to make a serial dilution by following specific dilution factors for the preparation of
each sample. For this procedure to be successful the first test tube prepared should be #5 (1.5mM) and then subsequent dilutions should take place using this sample. The 1.5mM solution
could be diluted to prepare the #4 0.5mM sample by using 1.67ml of solution in 3.33ml of distilled water to make a ⅓ dilution. The subsequent test tube #3 0.25mM could be prepared via a ½ dilution using 2.5 ml of #4 0.5mM and 2.5 ml of distilled water. The next dilution for #2 0.10mM would require 2ml of #3 0.25mM and 3ml of distilled water. Finally, the #1 test tube could be prepared using a ½ dilution using 2.5 ml of #2 0.1mM and 2.5ml of water. This technique is typically used to make very diluted solutions from once concentrated solution, but if
your dilutions were kept track of this method could work for this procedure. 2
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Related Questions
1. Presence of interfering contaminants in the sample is an example of this error.
2. A substance that shows the endpoint of titration
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PRELIMINARY QUESTION: Which of the following
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I.
The țitrant used is sulfuric acid solution.
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-
Insoluble in 5% NaOH
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Insoluble in 5% HCI
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One statement is not true regarding the determination of pka of Bromothymol Blue
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A.
В.
The absorption spectrum is the plot of
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C.
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pH
Indicator
1
4
7
8
9.
10
11
12
Phenolphtalein
Colorless
Pink
Bromthymol Blue
Methyl Orange
Yellow
Blue
Red
Yellow
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2. A colorless household solution was tested with the three indicators shown above. The
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Br2;
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[attached is the given data]
Questions:
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Procedure
Preparation of Dilute Solution of Vinegar
• Using a 10 mL pipette, transfer 10mL of vinegar into 100 mL volumetric flask.
• Dilute to mark of the volumetric flask using distilled water.
B. Titration of Diluted Solution of Vinegar
• Transfer 25 mL of diluted solution to 250 mL Erlenmeyer flask.
• Add 0.5 mL phenolphthalein indicator. Set aside.
• Transfer 50mL of 0.110 M NaOH into a 50 mL burette.
• Titrate the diluted solution until the phenolphthalein endpoint (very faint pink).
• Record volume of NaOH used.
Answer the question:
What is the experimentally determined concentration of acetic acid in your vinegar solution: (Please give your answer to three significant figures.)
______ M Acetic Acid
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solid sample)
0-928 mmol No.
0.0103 mmol NaOH 0078 m N.CO
Cannot be determined
012 mol NaC0, 197 minol NaHCO
129 mmol NaOH, 097ml Najco
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Calcelate
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52 (음)/ 아 to Solalicn.
A) 0.65
p) 0 구2
() o.81
D) 0.94
Calulete pt of
0-001 M oK H Poa solation
A) )
c) I.5
D) 2.5
NGOH
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N of
Nof slit of
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D
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Related Questions
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