Module 6 Unit 1 Assignment C

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Fanshawe College *

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MI-JUN ACE

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Chemistry

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Jan 9, 2024

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doc

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MODULE 6 UNIT 1 Assignment Part C By: Connie Warburton Show all calculations. 1. In the reaction : Mg 3 N 2(s) +3H 2 O (l) 3MgO (s) + 2 NH 3(g) If 10.3 g of magnesium nitride reacts with water, what is the percent yield of ammonia gas if 4.0 L of ammonia would be collected at 24 ˚ C and 100.2 kPa? (5 marks) 1 mol Mg 3 N 2 = (3 x 24.305g) + (2 x 14.007g) = 100.929g 10.3 g Mg 3 N 2 x 1 mol ÷ 100.929g = 0.102519375 = 0.102 mol Mg 3 N 2 0.102 mol Mg 3 N 2 x 2 mol NH 3 ÷ 1 mol Mg 3 N 2 = 0.204 mol NH 3 1 mol = 22.4 L 0.204 mol NH 3 x 22.4 L ÷ 1 mol = 4.5696 = 4.6 L NH 3 Actual yield ÷ Theoretical yield x 100% = 4.0 L NH 3 ÷ 4.6 L NH 3 x 100% = 87% 2. If magnesium is added to hydrochloric acid (HCl), hydrogen gas and magnesium chloride are made. If 3.46g of HCl is used, what is the percent yield of hydrogen gas if 0.625 L of H 2 will be produced at 141.9 kPa and 25°C? Mg + 2HCl H 2 + MgCl 2 1 mol HCl = 1.008g + 35.45g = 36.458g 3.46g HCl x 1 mol ÷ 36.458g = 0.0949037248 = 0.095 mol HCl 0.095 mol HCl x 1 mol H 2 ÷ 2 mol HCl = 0.0475 mol H 2 1 mol = 22.4 L 0.0475 mol H 2 x 22.4 L ÷ 1 mol = 1.064 L H 2 Vf = 1.064 L H 2 x 298 K ÷ 273 K x 101 kPa ÷ 141.9 kPa Vf = 0.8266738946 Vf = 0.827 L H 2 Actual yield ÷ Theoretical yield x 100% = 0.625 L H 2 ÷ 0.827 L H 2 x 100% = 76% Total: 10 marks Submit your assignment using the drop box on the Assignment page for this unit. Remember to include references. 1
References: Fanshawe College (2023) “Module 6 unit 1 presentation” retrieved from https://olmoodle.ontariolearn.com/mod/scorm/player.php? a=8782¤torg=articulate_rise&scoid=17774&sesskey=UyugQgN7Bq& display=popup&mode=normal Ptable.com (2023) “Periodic Table” retrieved from http://ptable.com/image/periodic-table.svg 2
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