Petree_Alan_M05_8-2

2. Objectives 172.16.1.2 172.16.2.2 192.168.1.2 64.100.1.2 Part 1: Configure IP Addresses as per given table on all devices Part 2: Configure Single Area OSPF on R1, R2 and R3 Part 3: Propagate a Default Route for internet Part 4: Verify Connectivity

19 20 Using any DNS query tool (e.g., NSLOOKUP on Windows, or DIG for MacOS or Linux, or any online DNS query tool) determine the IPv4 address (A record) associated with the domain name: www.umsl.edu 134.124.251.142 8.8.8.8 134.124.1.234 134.124.2.2 Using any DNS query tool (e.g., NSLOOKUP on Windows, or DIG for MacOS or Linux, or any online DNS query tool) determine the IPv4 address (A record) associated with the domain name: citil.umsl.edu 134.124.251.142 8.8.8.8 134.124.1.234 134.124.2.2

Branch Office Host 192.168.1.1 Source: 192.168.1.1 Dest: 192.168.2.1 R1 1.1.1.1 ENCRYPTED Source: 192.168.1.1 Dest: 192.168.2.1 Tunnel VPN Header 2.2.2.2 R2 Source: 1.1.1.1 Dest: 2.2.2.2 Enterprise Network File Server 192.168.2.1 Source: 192.168.1.1 Dest: 192.168.2.1 Above you see a branch office that is connected to the enterprise network using an internet connection. The VPN has been established between the two routers. This is how it works:

Figure 01 172.14.1.1 255.255.255.0 41.11.21.2 255.0.0.0 41.11.21.1 255.0.0.0 Ser0/0 172.14.1.2 255.255 255.0 © Ser0/1 © Ser0/0 192.168.2.100 255.255.255.0 Ser0/0 192.168.1.100 262XM 255.255.255.0 RouFa0/0 2621XM Router1 2621 XM RouFa0/0 Fa0/3 Fa0/2 Fa0/3 Fa0/2 Fa0/1 Fa0/1 2960-24TT Switcho 2960-24TT PC-PT PC-PT PCO PC-PT PC1 PC-PT PC2 Switch1 PC3 192.168.1.1 255.255.255.0 192.168.1.2 255.255.255.0 192.168.2.1 255.255.255.0 192.168.2.2 255.255.255.0 A fully specified route is needed to be set up in the above figure Yes No

0-2021-Computer Networks What subnet mask would you use for the 172.172.0.0 network, such that you can get 300 subnets and 100 hosts per subnet? [Estimated time to answer the question: 5 mins] Answer: Next page 8 9. 10 11 12 13 14 15 4 6. 7 10:13 AM C ENG 3/25/2021 acer 5

131.107.893.3.57.0200.200.5.2191.107.2.10127.0.0.1Which address class (es) will allow you to have more than 1000 hosts per network?Which address (es) will allow only 254 hosts per network?

172.22.31.0/26 Server GO/2 GO/O GO/1 172.22.34.64/27 R1 172.22.34.96/28 s1 S2 PC1 PC2 Addressing Table Device Interface IP Address Subnet Mask Default Gateway GO/0 172.22.34.65 255.255.255.224 N/A R1 GO/1 172.22.34.97 255.255.255.240 N/A GO/2 172.22.34.1 255.255.255.192 N/A Server NIC 172.22.34.62 255.255.255.192 172.22.34.1 PC1 NIC 172.22.34.66 255.255.255.224 172.22.34.65 PC2 NIC 172.22.34.98 255.255.255.240 172.22.34.97 1. Build and configure given topology using Packet Tracer. 2. Configure an ACL (100) to permit FTP and 1CMP. 3. Filter the ACL that allows traffic belonging to 172.22.34.64/27 network. 4. Configure the destination address. Filtering traffic for a single destination, which is the server. 5. All other traffic is denied, by default. 6. Verify the access list. 7. Apply the ACL on the correct interface to filter traffic (R1). The traffic that ACL 100 applies to is inbound from the network connected to the Gigabit Ethernet 0/0 interface. 8. Verify the ACL implementation.…

NO GPT ANSWER PLEASE : Network 192.168.40.4 needs to be divided into 12 subnets, with at least 18 hosts in each subnet. What subnet mask would you use to accomplish this design goal? A. 255.255.255.240 B. 255.255.255.252 C. 255.255.255.224 D. 255.255.255.248

Network

p.4/4 6. Host IP Address 171.68.99.71 Major Network Mask 255.255.0.0 Major (Base) Network Address Major Network Broadcast Address Total Number of Host Bits Number of Hosts Subnet Mask 255.255.240.0 Number of Subnet Bits Number of Host Bits Number of Useable Hosts per Subnet Subnet Address for this IP Address IP Address for the 1st Host on this Subnet IP Address for the Last Host on this Subnet Broadcast Address for this Subnet

What valid host range is the IP address 172.16.10.22 255.255.255.240 a part of? A) 172.16.10.20 through 172.16.10.22 B) 172.16.10.1 through 172.16.10.255 C) 172.16.10.16 through 172.16.10.23 D) 172.16.10.17 through 172.16.10.31 E) 172.16.10.17 through 172.16.10.30Please explain the answer also.

Help please

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The below network diagram consists of Rustaq, Middle and Sohar networks. Both Sohar and Rustaq network uses UTP cable with data rate of 100 Mbps. A) What is the network address of Rustaq, Middle and Sohar networks? B) Identify the category of the UTP cable in Sohar and Rustaq networks. C) What is the need of DNS & DHCP server in Sohar networks?

Find & define the IP addressing problem. 192.168.1.33 Default gateway 192.168.162 1900 FO/27 FO/26 192.168.1.66 Default gateway: 192.168.1.95 FOO 192.168.1.62/27 SO/O FO/2 50/0 2950 192.168.1.65 Default gateway 192.168.1.95 192.168.1.97/27 192.168.1.100/27 F0/3 FO/1 FOO 192.168.1.95/27

10.129.255.100 255.248.0.0 How many addresses in this subnet? Select one: a. 2120 b. 2^4 C. 2424 O d. 2^19

Given the following information (address pairs)192.171.247.18 178.221.56.1 10.10.11.1192.173.252.19 178.221.24.1 10.10.12.1What subnet mask will place these addresses on different network segments and provide the greatest number of hosts for heach network segments? How many hosts? What's the first and last host address)What subnet mask will place these addresses on the same address and provide the

What is the network address and subnet mask of the hidden subnet (xxXx.XXx.XXXX.XXXX/xX) subnet? The whole network has a network address and subnet mask of 192.168.0.0/25

Match each description with an appropriate IP address. (Not all options are used.) a link-local address v [ Choose ] 172.18.45.9 169.254.1.5 240.2.6.255 a public address 198.133.219.2 127.0.0.1 an experimental address [ Choose ] a loopback address [ Choose ]

Specify the class of address and the subnet ID for the following cases: (a) A packet with IP address 127.168.28.31 using mask pattern 255.255.255.0 (b) A packet with IP address 150.126.21.14 using mask pattern 255.255.255.128 (c) A packet with IP address 188.145.86.1 using mask pattern 255.255.255.128 You are required to show details steps for your provided answer. For Subnet ID, you need to determine which bits are part of the subnet and then convert only those bits to decimal to get the ID.

Client (Shahid) 198.150.11.34 Client (Khalid) 198.150.11.163 FE:ED:F9:44:45:66 R1 R2 FE:ED:F9:EF:ED:EC 10.1.1.1/24 10.1.1.2/24 198.150.11.45 FE:ED:F9:FE:44:AF 198.150.11.33 DD:EC:BC:AB:04:AC 198.150.11.161 DD:EC:BC:43:7B:34 198.150.11.165 FE:ED:F9:89:54:23 In the above network diagram, IP and MAC addresses are given for network nodes. Suppose Host1 (Shahid) sends a datagram to Host2 (Khalid). What IP and MAC addresses (source and destination) will be written in IP and Data link layer headers respectively, for the following intermediate points from Host1 to Host2? a) Host1 to Router1 (R1) b) Router1 to Router2 (R2) c) Router2 to Host2

An organization is granted a block of addresses with  the beginning address 14.24.74.0/24. The organization needs to have 5 subnets as shown below: 3 subnets ,each with 64 address 2 subnets ,each with 32 address

192.168.30.10o 192.168.70.1 192.168.2.2 192.168.0.2 Question 1: The subnet mask in the following network is 255.255.255.0. Answer the following: (a) How many subnets are in the network? (b) Write the Network address of each subnet. (c) Write the Default Gateway of each subnet. 192.168.60.2 192.168.1-1 Susitch X 192.168.1.2 192.168. 6o. (a) No. of Subnets? X. 192.168.40.1 192.168.2.1 192.162.80.3 192.168.80.1 192.168.40.2 Switch 192.168.10.1 192.168.20.1 Suitch 192.168.0.1 192.168.0.10 192.168,30.1 write Netwarde address and Default Gateray ih this Table 192.168.20.10 192.168.10.10 Network Address A. B.

8. Design 8 subnets for a company with the site address 201.75.38.0. a)  What is the network mask? b)  What is the subnet mask? c)  How many hosts (addresses) can be supported on each subnet? d)  What is the address of the 5th subnet?