CS1101-Unit03 programming assignment

Instructions: In the code editor, you are provided with a treasureChestMagic() function which has the following description: Return type - void Name - treasureChestMagic Parameters - an address of an integer Description - updates the value of a certain integer randomly You do not have to worry about how the treasureChestMagic() function works. All you have to do is ask the user for an integer and then call the treasureChestMagic() function, passing the address of that integer you just asked. Finally, print the updated value of the integer inputted by the user.   Please create a main code for my function that works with this. This is my code: #include<stdio.h>#include<math.h> void treasureChestMagic(int*); int main(void) {    // TODO: Write your code here     return 0;} void treasureChestMagic(int *n) {    int temp = *n;    int temp2 = temp;     *n = *n + 5 - 5 * 5 / 5;     temp2 = (int) pow(2, 3);     if(temp % 3 == 0) {        *n = temp * 10;    } else if(temp %…

/* * rotate4 - Rotate x to the left by 4 *   Examples: rotate4(0x87654321) = 0x76543218 *   Legal ops: ~ & ^ | + << >> ! *   Max ops: 10 *   Rating: 2 */int rotate4(int u) {  return 2;}  Do not use any control constructs such as if, do, while, for, switch, etc.

while (*psz_2 != 0) {;u8_c = *psz_2;;if (u8_c > 0x2F) {;*psz_1 = u8_c | 0x20;;} else {;*psz_1 = u8_c;;}

JAVA CODE PLEASE Functions With No Parameters and Return Values Quiz by CodeChum Admin Create a function named banner that prints “CodyChum” with a newline. In the main function, write a program that accepts an integer input which would serve as an inclusive stopping point of a loop iteration that starts at the value of 1. If the number that loops through the range is divisible by either 2 or 3, then call the banner function, otherwise just print the number. Input 1. One line containing an integer Output First line is the integer user input. Succeeding multiple lines containing an integer or “CodyChum” 10 1 CodyChum CodyChum CodyChum 5 CodyChum 7 CodyChum CodyChum CodyChum

C++ Programming Language: Enhance the code given by outputting: The largest number of the sequence a0 ,a1 ,a2 , ..., ak. The position of the largest number Test your program for the following values of x: 75, 111, 678, 732, 873, 2048, and 65535. Example: "For example, for the input sequence: 75, 226, 113, 340, 170, 85, 256, 128, 64, 32, 16, 8, 4, 2, 1, the program output should contain the following: The largest number of the sequence is 340 The position of the largest number is 4"   Code Given:   #include <iostream> #include <iomanip>   using namespace std; int main() { long x; int count; long a_n; cout << "Enter a nonnegative integer: "; cin >> x; cout << endl; count = 0; a_n = x; cout << a_n << ", "; while (a_n !=1) { if (a_n %2==0) a_n = a_n / 2; else a_n = 3 * a_n + 1; count++; cout << a_n <<", "; } cout << endl; cout << "The integer k such that a_k = 1 is " << count << endl; return0; }

Using the starter code below, write a program that asks a user for two points (x1, y1) and (x2, y2), then computes the area of the circle for which (x1, y1) is the center and (x2, y2) is on the circle's perimeter. The program should define and use 3 functions: distance(x1, y1, x2, y2): computes and returns the distance between two points • area(r): computes and returns the area of a circle with radius r • main(): asks user for input, calls the other functions, and prints the answer. The input and output of the program should look similar to this: X for center point: 0 Y for center point: 0 X for perimeter point: 1 Y for perimeter point: 1 Area of circle centered at (0.0, 0.0) with radius 1.414213 is 6.283185. Hint 1: Area of a circle = n? Hint2: Distance between 2 points = sqrt(x2-X12 + (Y2 - Y1)²) Starter code: import math def distance(x1, y1, x2, y2): #Add code to compute and return distance between (x1, y1) and (x2, y2) def area(r): #Add code to compute and return area of circle…

python: numpy def not_stealing(items):    """    While you're shopping, you notice that some items you've picked up do not have a price tag.    Do you steal them? NO! Instead, you decide to be a good person and replace them with another item    that does have a price.    - Items with no price will have a value of np.nan.    - Replace np.nan values with a random price between $5 and $9, inclusive.    - Return the average of the new prices in the array, rounded to 2 decimal places.    - DO NOT REMOVE random.seed(1)     Args:        items (np.array)    Returns:        float     >> items = np.array([4.63, np.nan, 3.78, 7.12, 12.35, 7.19, np.nan, 1.50, 2.41])     >> not_stealing(items)    5.66     """    #DO NOT REMOVE#    random.seed(1)    ##############       # items = np.array([4.63, np.nan, 3.78, 7.12, 12.35, 7.19, np.nan, 1.50, 2.41])    # print(not_stealing(items))     # items = np.array([np.nan, np.nan, 6.18, np.nan, 18.42, 2.67, 9.14, np.nan, 14.32])    #…

Write a program that generates random numbers between -25 and 25 by using the randint function. The program will add up the numbers and terminate when the sum of the values becomes zero. The program should contain the following functions: add()    : add up the values main(): the function where the program execution should begin and end.  randomgen(): a function that returns a number between -25 and 25 A global variable subsetsum that keeps track of the sum The program should output the count of the number of values generated before exiting saying that the subset sum was zero.

The purpose of (int) in the statement: int x = (int)(Math.log(16)); is to ……………………