answer_2 (2)

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Seminole State College of Florida *

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1054C

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Electrical Engineering

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Dec 6, 2023

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docx

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These percent errors are exceedingly high, indicating a possible error in either the experimental procedure, the theoretical value assumptions, or the experimental impulse recorded. In typical physics experiments, a percent error in the range of a few percent is considered acceptable, depending on the precision of the measurement instruments. Values as high as those calculated here usually suggest that there may be a fundamental issue with the experiment that needs to be addressed. The calculation also does not compare the impulse to the change in momentum; it compares the values obtained between two trials of the same type of measurement. Using the impulses from table (69.75 N·s for Trial 1 and 107 N·s for Trial 2): Percent Difference: \( 0.4214 \100 = 42.14% \) However, the percent differences you reported earlier are 190.2% and 194%, which are significantly higher than what this calculation yields. There may have been a misunderstanding or error in your original calculation. The corrected percent difference for the impulse between the two trials is approximately 42.15%. This is a significant deviation from the percent differences of 190.2% and 194% reported earlier. The original calculation of the percent differences may have been incorrect or based on different values. let's examine the data you provided: 1. Table Data: - Mass of Cart: 0.666 kg - Trial 1: vi = -1.249 m/s, vf = 1.380 m/s, Δp = 1.751 kg·m/s, J = 69.75 N·s

- Trial 2: vi = -1.048 m/s, vf = 1.380 m/s, Δp = 1.617 kg·m/s, J = 107 N·s 2. Graphs for Trial 1: - The graph showed a large impulse of 135.5 N·s and a smaller impulse of 69.75 N·s. - The velocity graph indicated a change in velocity (∆v) consistent with the velocities reported for Trial 1 in your table. 3. Graphs for Trial 2: - The force graph showed a positive impulse of 107.0 N·s and a negative impulse of -3.919 N·s. - The velocity graph indicated a change in velocity (∆v) of 1.828 m/s, which matched the velocities reported for Trial 2 in your table. Issue Identification : The impulses recorded in your table (69.75 N·s for Trial 1 and 107 N·s for Trial 2) do not match the calculated theoretical impulses using the mass of the cart and the changes in velocity. The theoretical impulse should be the product of mass and the change in velocity (∆v), which in both trials provided much lower values than the experimental impulses recorded in the graph data. Possible Sources of Error : - Misinterpretation of Impulse: The impulse in physics is the product of the force and the time over which it acts (area under the force-time curve). It appears that the larger impulses (135.5 N·s for Trial 1 and 107.0 N·s for Trial 2) were not considered in the table. Instead, the smaller impulse from Trial 1 and the positive impulse from Trial 2 were used, which might be incorrect.

- Inconsistency in Data: If the graph data is correct, the table should reflect the larger impulse as the change in momentum, which is not the case here. Resolution Steps: - Correct the Impulse Values: If the larger impulses from the graphs are indeed the correct values for the impulse given to the cart, these should be used in the table. - Recalculate Theoretical Impulse: Ensure that the correct change in velocity is used. The change in velocity should be the difference between the final velocity and the absolute value of the initial velocity since both velocities are in opposite directions. - Recalculate Percent Error: After recalculating with the corrected impulse values obtained from the graphs: For Trial 1: - Theoretical Impulse: 0.087246 N·s - Percent Error: 155207.98% For Trial 2: - Theoretical Impulse: 0.221112 N·s - Percent Error: 48291.77%

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