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12/16/22, 9:15 AM Review Test Submission: Quiz_07 ELEC8900-30-R-2022F ... Home Get Help Courses e et e e e e on ELEC8900-30-R-2022F Adv. Energy Storage Systems Evaluation Review Test Submission: Quiz_07 Review Test Submission: Quiz_07 User Jayraj Manishkumar Pandya Course Adv. Energy Storage Systems Test Quiz_07 Started 11/4/22 6:01 PM Submitted 11/4/22 6:20 PM Due Date 11/11/22 6:54 AM Status Completed Attempt 16 out of 20 points Score Time Elapsed 19 minutes out of 20 minutes Instructions Backtracking is prohibited - You will not be able to go back to the previous question to change the answer or come back to answer the question later. You will be able to navigate only forward through the quiz. Please ensure to answer the current question before going to the next. '>' will help navigate to next question. Results All Answers, Submitted Answers, Correct Answers Displayed Question 1 0 out of 4 points https://blackboard.uwindsor.ca/webapps/assessment/review/review.jsp?attempt_id=_ 10210142 _1&course _id=_ 165126 1&content_id= 2142089 1&o... 1/5
12/16/22, 9:15 AM Review Test Submission: Quiz_07 ELEC8900-30-R-2022F ... Refer to the ECM, Figure (4) of a battery. Given that a constant current i(k) = 1A is applied to the battery and the resulting terminal voltage v(k) is measured 2 consecutive times, the measured voltages v(1),v(2) are given by 3.909V, 3.993V respectively. Then, the current is changed to i(k) = 2A and the resulting terminal voltage v(k) is measured 2 consecutive times. The measured voltages v(3),v(4) are given by 4.099V, 4.202V respectively. Use the least squares estimation approach to estimate the internal voltage E(k) and internal resistance I, of the battery. Assume that E and R, remain constant through this process. AW EMFf v(k) Figure 4: Equivalent Circuit Model of a battery Selected Answer: ¢ E = 3.8705V,Ro = 0.165Q Answers: & E = 3.7515V,Ro = 0.1995Q E = 3.8905V,Ro = 0.145Q E = 3.8705V,Ro = 0.165Q E = 3.6505V,Ro = 0.130Q Question 2 4 out of 4 points https://blackboard.uwindsor.ca/webapps/assessment/review/review.jsp?attempt_id=_10210142_1&course_id=_165126_1&content_id=_ 2142089 1&o... 2/5
12/16/22, 9:15 AM Review Test Submission: Quiz_07 ELEC8900-30-R-2022F ... Ro —i(k) A + V;(s)+—__—' v(k) 0 Figure 1: Equivalent circuit model of a battery. The open circuit voltage of the battery has the following model: Va(s) =ko + kys™" + kos ™2 + kas > + kys™ + kss + ke In(s) + k7In(1 s) (1) where k0 = —9.0818, k1 = 103.0870, k2 = —18.1846, k3 = 2.0625, k4 = —0.1018, k5 = —76.6037, k6 = 141.1994, and k7 = —1.1168, These parameters were computed for SOC values s [0, 1] after they were linearly scaled to s’ [.175,.825]. The internal resistance of the battery is Ry = 0.2Q. The SOC of the battery is 50%, i.e., s = 0.5. Compute v(k) when the current through the battery is i(k) = 0 A. Selected Answer: @, 3.825V Answers:; 4.016V & 3.825V 3.752V 3.672V Question 3 4 out of 4 points https://blackboard.uwindsor.ca/webapps/assessment/review/review.jsp?attempt_id=_10210142_1&course_id=_165126_1&content_id=_ 2142089 1&o... 3/5
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