Lab 2- Nodal Analysis

Consider the series-parallel circuit shown in the figure below with various multimeters connected in the circuit. Assum that XMM1 has been configured in ammeter mode, and XMM2 has been configured in voltmeter mode. XMM1 R1 1kQ XMM2 R2 R3 V1 1kQ 1kQ 12V 3.1: Redraw the circuit replacing XMM1 and XMM2 by their equivalent circuit models 3.2: Assume that XMM2 was incorrectly configured in ammeter mode. Redraw the equivalent circuit from 3.1 and compute the current that would be measured by the ammeter in this scenario. Hil-

Q4

180 is the answer amount of ohms needed on the oscilliscope. I need to transpose the equation to solve for R. I must work out an equation that equals 180 ohms R resistance that gives off 50mA of current using the transposed equation. Series impedence ,inductive reactive, phase angle formulas may need to be used. I need to get as close to 180 ohms as possible.

Using these diagrams of circuits, what are the steps and materis to create these kind of circuits?

A component requires 6.3-V across it with a current of 0.3 V. A second component requires 12.6-V at 0.15A.  The two components are connected in series. What is the value of resistor that must be connected across the 12.6-V component to allow it to operate properly when in series with the 6.3-V component?

3.  a. by applying Kirchhoff's junction rule to two junctions find the current I5.  b. by applying Kirchhoff's loop rule, find the resistances R2.  c. by applying Kirchhoff's loop rule, find the reistences R3.

Shown in the figure below is an electrical circuit containing three resistors and two batteries. I₁ 0= 4 + L . ww R3 R₂ ww 1₂ R₁ ww Write down the Kirchhoff Junction equation and solve it for I, in terms of I₂ and I3. Write the result here: 1₁ = 12-13 R₂=552 R₂ = 132 13 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. - IzR3 − LR₁ + 14 + 10 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components 4V, R₂, and R₁. 0 = 4-1₂R₂-11R₁ The resistors in the circuit have the following values: R₁ = 12 Solve for all the following (some answers may be negative): I₁ = 27.78 X Amperes 1₂ = 28.84 X Amperes 13 = 1.060 X Amperes NOTE: For the equations, put in resistances and currents SYMBOLICALLY using variables like R₁,R₂,R3 and 11,12,13. Use numerical values of 10 and 4 for the voltages.

For R1=55, R2=D125, R33D135, R4=15, R5=40, R63D90 and V1=4 V in the shown figure, use circuit reduction and current/voltage division rules to calculate the following: R6 R1 R5 R3 R2 V1 V2 R4 V13= V2=