Lab 2- Nodal Analysis

Consider the series-parallel circuit shown in the figure below with various multimeters connected in the circuit. Assum that XMM1 has been configured in ammeter mode, and XMM2 has been configured in voltmeter mode. XMM1 R1 1kQ XMM2 R2 R3 V1 1kQ 1kQ 12V 3.1: Redraw the circuit replacing XMM1 and XMM2 by their equivalent circuit models 3.2: Assume that XMM2 was incorrectly configured in ammeter mode. Redraw the equivalent circuit from 3.1 and compute the current that would be measured by the ammeter in this scenario. Hil-

Q4

Which of the following statements are correct for the circuit below? Thanks to the capacitors I – C1 and C2, the voltage gain of the circuit increases. II – Capacitors C1 and C2 are coupling capacitors and provide an isolation function between AC and DC voltages in the circuit. Thanks to the III – RE resistor, the voltage gain of the circuit increases. Thanks to the IV – RE resistor, the stability of the circuit increases. The V – C3 Capacitor is a bypass capacitor and prevents the loss of voltage gain. Capacitor VI – C3 is a coupling capacitor and has no effect on the voltage gain in the circuit. VII – As the value of the source internal resistance Rs increases, the voltage gain decreases. VIII – The voltage gain decreases as the value of any RL load to be added to the circuit increases

A dc generator and a battery are connected to a resistive load RL in the figure below. For each, determine the value of RL for maximum power transfer to RL. Next is to determine RL to 75% efficiency

Two batteries are connected in parallel delivering power to a power resistor. The first battery has an open circuit voltage of 12.6 V and an internal resistance of 0.2 ohm. The second battery has an open circuit voltage of 12.2 V and an internal resistance of 0.3 ohm. Find the maximum power delivered to the load resistance.

6. A Thevenin de equivalent circuit always consists of an equivalent.. a. AC voltage source b. capacitance c. DC voltage source d, resistance 7. The superposition theorem is useful for the analysis of. ***** a. single-source circuits. b. only two-source circuits. c. multi-source circuits. d. no source circuits.

What can you learn about Series-Parallel Circuits?

True/False: Consider connecting a Load Resistance across R2. Loading Effect is less when voltage across R2 'with load' is close to the Voltage 'without load' * Vin R2 V. out True O False

PLS PLS SHOW COMPLETE SOLUTION AND WRITE LEGIBLY. DRAW CIRCUIT DIAGRAM. PLS PLSS SHOW HOW THE EQUATIONS REDUCED TO NEEDED.

1. Using Series-Parallel concept, Find the following for the given circuit. The value of the power supply and resistances are given in Page-4. a) the current supplied by the source b) the voltage drops across each resistor c) the r dissipated by R3 R1=45kn R2=2kn R3=22kQ R4=14kn R5=17kn R6=85kn V1=24 v R₁ R₂ V₁ R₂ R₂ R₂

(II) Explain what happens if the topology is modified as shown in figure below. VREFO- ww Qz

i need the answer quickly

Q1) For the circuits shown in figure below, obtain the equivalent resistance at terminals a-b. sa 200 ww- 20

180 is the answer amount of ohms needed on the oscilliscope. I need to transpose the equation to solve for R. I must work out an equation that equals 180 ohms R resistance that gives off 50mA of current using the transposed equation. Series impedence ,inductive reactive, phase angle formulas may need to be used. I need to get as close to 180 ohms as possible.

A 3-ohm resistor is connected in parallel with a variable resistor R. the parallel combination is the connected in series with a 6-ohm resistor and connected across a 120Volt source. Find the minimum value of R if the power taken by R is equal to the power taken by the 6 ohm resistor.

Using these diagrams of circuits, what are the steps and materis to create these kind of circuits?

is made from a combination of A mixed resistors circuit as shown in Figure parallel and series circuits. The values of the resistances mentioned in the circuit are in Ohm (2) and the supply voltage is in Volt (V). Determine the: (i) Current through the circuit (I). (ii) Voltage drop (V) across the circuit. 0.6 0 4 0 0.5 0

compare the charasteristics of series with those of parallel circuit s,what are their differences ? their likeness ?

In an electrical circuit four resistors are connected in parallel and their equivalent resistance is 50ohms. Find the value of each resistors if the currents through each impedance are 0.8, 0.4, 0.6 and 0.2 ampere.

solve all clear and correct or dislike

If two resistors are connected in parallel and R1 is shorted, what are the current and voltage in R2? Explain If two resistors are connected in parallel and R1 is open, what are the current and voltage in R2? Explain Which has more excellent equivalent resistance, those resistors in parallel or those in series? Explain

A component requires 6.3-V across it with a current of 0.3 V. A second component requires 12.6-V at 0.15A.  The two components are connected in series. What is the value of resistor that must be connected across the 12.6-V component to allow it to operate properly when in series with the 6.3-V component?

What is the difference between the cut-off voltage VGS0 f and the narrowing voltage Vp? Explain this with the diagram

3.  a. by applying Kirchhoff's junction rule to two junctions find the current I5.  b. by applying Kirchhoff's loop rule, find the resistances R2.  c. by applying Kirchhoff's loop rule, find the reistences R3.

B=58

Units of R1 and R2 are Ohm   Electric Circuits

Shown in the figure below is an electrical circuit containing three resistors and two batteries. I₁ 0= 4 + L . ww R3 R₂ ww 1₂ R₁ ww Write down the Kirchhoff Junction equation and solve it for I, in terms of I₂ and I3. Write the result here: 1₁ = 12-13 R₂=552 R₂ = 132 13 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. - IzR3 − LR₁ + 14 + 10 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components 4V, R₂, and R₁. 0 = 4-1₂R₂-11R₁ The resistors in the circuit have the following values: R₁ = 12 Solve for all the following (some answers may be negative): I₁ = 27.78 X Amperes 1₂ = 28.84 X Amperes 13 = 1.060 X Amperes NOTE: For the equations, put in resistances and currents SYMBOLICALLY using variables like R₁,R₂,R3 and 11,12,13. Use numerical values of 10 and 4 for the voltages.

PLEASE ANSWER BOTH QUESTIONS FOR UPVOTES. NO UPVOTE IF ONLY ONE HAS AN ANSWER. PUT ONLY BRIEF EXPLANATIONS ON CHOOSING THE CORRECT ANSWERS. THANK YOU