lab3

3. A sinusoidal waveform is displayed on a c.r.o. screen. The peak-to-peak distance is 5 cm and the distance between cycles is 4 cm. The 'time'switch is on 100 µs/cm and the 'volts/cm' switch is on 10 V/cm. Determine (i) angular frequency (ii) peak (iii) rms value of voltages (iv)Time period and (v) form factor.

-) Below are two voltage patterns measured from an oscilloscope. The voltage stage of the CHI probe is 5 V / div, the CH2 probe voltage stage is 10 V / div and the time axis is 2ms / div. According to this information, a) What are the peak to peak and rms voltage values ​​of the voltages in CHI and CH2? b) What is the frequency of the voltages in Hz? c) How many degrees is the phase difference between the two voltages, which voltage is leading?

Q18. An AC waveform is shown in figure B3. 4 10 20 30 40 50 70 100 Time (ms) 110 -2 -3 -4 -5 Figure B3 i) For the above waveform, determine a. Peak-to-peak voltage b. Time period c. Frequency ii) For the above waveform, determine a. Peak Factor b. Form Factor

a. A circuit with half-wave rectified signal has a dc voltage of 0.318Vm. The rms value of the ac component of the output signal is 0.385Vm. Calculate the percentage ripple of a half-wave rectified signal.

(a) What is the frequency in Hertz and rad/s of the voltage waveform shown on Figure Q1? (b) Calculate the average voltage and rms ac voltage of the waveform shown on Figure Q1. (c) Calculate the total rms voltage of the waveform shown on Figure Q1. (d) The voltage on Figure Q1 is connected across a 0.15 2 resistive load. Calculate the power dissipated in this resistor.

3-9 An rms ac voltmeter and a peak-to-peak-reading ac voltmeter are to be used to determine whether three ac signals are sinusoidal. Deter. mine whether the signals are sinusoidal if the following readings are obtained First signal Second signal Third signal peak-to-peak reading = 35.26 V rms reading. - 12.00 V peak-to-peak reading - 11.31 V rms reading = 4.00 V peak-to-peak reading = 25.00 V rms reading -8.83 V

A sinusoidal waveform is displayed on a c.r.o. screen. The peak- to-peak distance is 5 cm and the distance between cycles is 4 cm. The ‘time ’ switch is on 100 μs/cm and the ‘volts/cm’ switch is on 10 V/cm. Determine (i) frequency (ii) peak and rms value of voltages (iii)Time .

١-The PMSM used in the industry due to: a- Their low noise. b- Their easy control arrangement. c- Their efficiency. 2- The BLDCM used in the industry due a- Their low noise. b- Their easy control arrangement. - Their efficiency. 3- The (PMSM) supplied by: a- DC voltage. b- AC voltage of sinusoidal waveform. C- AC voltage of trapezoidal waveform. Choices

8. Liquids with solid impurities a) Have higher dielectric strength b) Of large size have higher dielectric strength c) Have lower dielectric strength as compared to pure liquids d) None of the above 9. Peak to peak ripple is defined as a) the difference between average de voltage and peak value b) the difference between maximum and minimum de voltage c) the difference between maximum ac and average de voltages d) the difference between ac (rms) and average de voltages 10. In a Cockroft-Walton circuit, input voltage 100 kV load current 25 mA, supply frequency 100 Hz, each capacitor 10 nF. The optimum no. of stages for maximum output voltage is a) 1 b) 2 c) 10 d) 35

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Answer only for (c2 (!) )

Full-wave rectified sine wave circuit is used to measure the RMS value of a half square wave with the help of PMMC meter. The meter was actually calibrated for sine wave. The circuit uses a meter movement with a full scale deflection current of 200uA and internal meter resistance of 5kΩ. Assuming Non-ideal diodes having resistance 1kΩ, Analyze the circuit to determine the value of series multiplier resister and the corrected RMS voltage, if meter is to read 225V RMS full-scale.

For the CRO square voltage waveform is shown in Figure. The 'time/cm' switch is on 5 ms/cm and the 'volts/cm' switch is on 2 V/cm. Calculate (a) the periodic time, (b) the peak to peak voltage, (c) the maximum voltage, (d) the time taken to complete half cycle The periodic time The peak to peak voltage The maximum voltage The time taken to complete half cycle

Facts A clipper is a device that removes either the positive half (top half) or negative half (bottom half), or both positive and negative halves of the input AC signal. In other words, a clipper is a device that limits the positive amplitude or negative amplitude or both positive and negative amplitudes of the input AC signal. In some cases, a clipper removes a small portion of the positive half cycle or negative half cycle or both positive and negative half cycles. In the below circuit diagram, the positive half cycles are removed by using the series positive clipper. Question: In your own opinion. Why do we need to clip a certain amount of voltage in positive or negative or on both sides? What is the benefit of that in our devices or circuits in doing such thing?

Listen Regarding a Sine wave of an A.C. voltage (pictured below for reference), changing the Volts per division setting results in which of the following? O a) Changes the actual frequency of the waveform. O b) Changes the actual period of the waveform. O c) Changes the actual voltage level of the waveform. O d) Has no effect on the actual voltage level, period or frequency of the waveform.

A. The value of: A=5 ms C= 15 ms Peak to peak = 10 B D Figure 1 (a) From Figure 1 above, identify the frequency (f), value of time at A, B, C, D, period (T) and the RMS.

1. Explain in detail about voltage harmonics and current harmonics .

Please show you detailed solution Number 10 A voltage of 250 volts at 50 Hz is impressed on a circuit having a 60-ohm resistor, 35-?F capacitor, and a 0.25-henry inductor in series. Determine power factor. A. 0.979 C. 0.924 B. 0.862 D. 0.707

An alternating current varying sinusoidally with a frequency of 50 Hz has anrms value of 20 A.a) Determine the instantaneous value at 0.0025 seconds.b) Determine the instantaneous value, 0.0125 seconds after passingthrough a positive maximum value.c) At what time, measured from a positive maximum value, will theinstantaneous current be 14.14 A?

Consider the characteristics of alternating current (ac). Find the false statement below. A. Alternating Current is any current that periodically changes direction. B. The graph of an ac source shows the relationship between magnitude and time. C. The frequency of an ac signal refers to the noise on the signal. D. The period of an ac signal is the reciprocal of the frequency. O A. O B O D

5/1 IN4001 120 V 60 Hz R 5 k2 100 uF 1) Explain how this circuit works 2) Draw the waveform at the output (Vrl) for a sinusoidal signal at the input 3) What is the effective voltage of peak voltage in the secondary? 4) What is the peak voltage on the load? 5) What is the average voltage of the output (on the load)? 6) Calculate ripple on load

B1. For the CRO square voltage waveform is shown in Figure. The 'time/cm' switch is on 10 ms/cm and the 'volts/cm' switch is on 2 V/cm. Calculate (a) the periodic time, (b) the peak to peak voltage, (c) the maximum voltage, (d) the R.M.S voltage. The periodic time The peak to peak voltage The maximum voltage The R.M.S voltage

Q.B1 For the CRO square voltage waveform is shown in Figure. The 'time/cm' switch is on 50 ms/cm and the 'volts/cm' switch is on 5 V/cm. Calculate (a) the periodic time, (b) the peak voltage, (c) the time taken to complete half cycle. The periodic time is = The peak voltage is = The time taken to complete half cycle

What is the action of a capacitor in a Power Supply Circuit?*   a. To de-couple DC component of the rectified AC input b. To increase the DC component of the output wave. c. To remove DC component of the AC wave. d. None of the above.

Power Electronics