Lab_Report_4

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California Polytechnic State University, Pomona *

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1101L

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Electrical Engineering

Date

Jan 9, 2024

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docx

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13

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P a g e | 1 ECE 1101L – Lab 4 Series and Parallel Circuits Name: Leyi Zhou Group: L 10/04/2023
P a g e | 2 Introduction Background Theory: The Kirchhoff’s Voltage Law (KVL) says that the algebraic sum of all voltages in a loop is 0, ∑Vi = 0. Therefore, in series circuits, the values of current are the same in the loop. Besides, for circuits in series, the equivalent Req = Rtotal = R1 + R2 + R3 + … +Ri. Besides, the Kirchhoff’s Current Law (KCL) says that the algebraic sum of all currents entering a node is 0, ∑Ii = 0, I1 + I2 + I3 + … + Ii = 0. Therefore, in parallel circuits, the values of voltage are the same across parallel branches. Objective: In this experiment, we took measurements and calculated the voltages and the currents in different series circuits and parallel circuits, to verify the KVL and KCL. For Part 1 of this lab, we built a series circuit, measured the node voltages and found branch voltages from node voltages. Then, we calculated the currents through each resistor and verified the values of current were all the same. Furthermore, we verified the KVL from the measurements of branch voltages, and we used the voltage and current measurements to calculate the equivalent resistance of the circuit. Lastly, we used Ohmmeter to measure the total resistance, and compared the result with the equivalent resistance. For Part 2 of this lab, we measured the value of V1 between 2 nodes using the Voltmeter. For Part 3 of this lab, we used Cadence to build a series circuit, and ran the Bias Point Simulation of the circuit in PSpice and found the node voltages. We then calculated the branch voltages and verified that the KVL worked correctly around the loop. For Part 5 of this lab, we build a parallel circuit and measured the voltages across all resistors. Then, we found the values of current through each resistor from voltage measurements, and we wrote KCL at node B of this circuit. After that, we were able to find I in which I = I2 – I3 + I4.
P a g e | 3 Pre-Lab
P a g e | 4
P a g e | 5
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