Problem_Set_2_Group_O

Question 7 Smith's Computers is deciding whether to invest in prevention costs for its servers. Data regarding the decision between Investing or not is as follows: Cost of Equipment Working capital investment required Annual Activity Annual Sales (assume all cash) Annual Cash Expenses Repair Costs Depreciation Maintenance Supplies Retooling costs of equipment at Salvage value of equipment Life of project Year 6. Invest in Prevention $ 150,000 $ 35,000 $ $ $ $ $ $ $ $ 267,300 $ 165,000 11,250 $ 45,000 16,667 $ 30,000 $ 55,000 $ 65,000 3,000 9 $ Do Not Invest $ The working capital will be released for investment elsewhere at the end of the 9 years. Smith's Computers uses a 7% discount rate. (Ignore income taxes) Show all computations using the net present value format. Prepare separate computations for each project. Invest in Prevention

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Given the two machines' data Machine A Machine B First Cost P8,000.00 P14,000.00 Salvage value Annual operation 2,000.00 3,000.00 2,400.00 Annual maintenance 1,200.00 1,000.00 Taxes and insurance 3% 3% Life, years 10 15 Money is worth at least 16% Using equivalent uniform annual cost method, determine the value of alternative A and alternative B: ANSWER for ALTERNATIVE A: Blank 1 ANSWER for ALTERNATIVE B: Blank 2

Given the two machines’ data                                                       Machine A         Machine B First Cost                                     P8,000.00           P14,000.00 Salvage value                                             0                 2,000.00 Annual operation                          3,000.00                2,400.00 Annual maintenance                    1,200.00                1,000.00 Taxes and insurance                                 3%                        3% Life, years                                                   10                         15 Money is worth at least 16% Using equivalent uniform annual cost method, determine the value of alternative A and alternative B:

given the two machine's data

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QI\ a contractor want to invest his money in one of projects A or B if you know that the interest rate is 10%, choose the best altemative A or B using net present worth method ? A. B. Initial Investment 120,000 CU 135,000 CU Annual revenue Annual expenses Salvage vahie |Project life Cost of machines replaced every 3 years 15,000 CU\year 10,000 CU year 12,000 CU 12 years 17,000 CU year 11,000 CU year 20,000 CU 6 усars 3500 CU 3000 CU Q2 A company is planning to purchase a new equipment to increase the production and revemies. The cost of the equipment is 451105 CU and the equipment installation cost is 17% of its cost. Find the payback period for this equipment Year 1 Year 2 120,000 CU 130,000 CU 90,000 CU Year 3 Year 4 |100,000 CU Year 5 115,000 CU 90,000 CU Year 6 Q3 \ Machinery costs (60000 CU) and its useful life is (5 year). compute the schedule of depreciation and book value at the end of each year for the machinery by using the Sum of Year Digit method , if you know that the…

Subject: Engineering Economy

A28

5

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Given the two machines' data Machine A Machine B First Cost P8,000.00 P14,000.00 Salvage value Annual operation 2,000.00 3,000.00 2,400.00 Annual maintenance 1,200.00 1,000.00 Taxes and insurance 3% 3% Life, years 10 15 Money is worth at least 16%. What is the exact rate of return?

Required information Problem 14.056 The two machines shown are being considered for a chip manufacturing operation. Assume the MARR is a real return of 14% per year and that the inflation rate is 6.7% per year. A B Machine First Cost, $ -146,000 -820,000 -5,000 -70,000 M&O, $ per year Salvage Value, $ 40,000 200,000 Life, years 5 00 Problem 14.056.a: Compare two alternatives based on their AW values without inflation consideration Which machine should be selected on the basis of an annual worth analysis if the estimates are in constant-value dollars? What is the annual worth of the selected alternative? Select machine (Click to select]: wwwwwwwwwwww wwwwww... The annual worth of the alternative is $

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You are given the following estimated information about a proposed project: Investment cost $ 66,000 Annual cost $/Year 10,000 Salvage value 10,000 Economic life 6 years M.A.R.R 10% Answer questions 4 through 6 based on the above information 5- The future worth cost is closest to : Select one: a. $ 170,080 O b. $ 184,082 O c.$ 195,500 d. $ 165,000

Given two machines data USING EQUIVALENT UNIFORM ANNUAL COST METHOD

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D Question 16 A $60,000 outlay for a new machine with a usable life of 15 years is called O replacement expenditure operating expenditure O capital expenditure 4 pts O financing expenditure

a- At 10%, find PW for the following Table Warehouse cost equipment cost Installation cost Annual maintenance costs Annual Revenues Salvage Machine life 0 1 2 3 -90,000 b- A project with an IRR = 20%, it has the following NCF (S) X X 4000 (SUS) 50,000 46.000 Find X? 6,500 8,000 45,000 15,000 15 years

QUESTION 3 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% First cost, S Annual cost, $/year Salvage value, $ Life, years Machine A Answer the below questions: B-AW for machine B= First cost, $ Annual cost, $/year Salvage value, $ Life, years 15000 9752 4,000 Machine A Answer the below questions: C-AW for machine C = 15000 Machine B 15892 4,000 22023 QUESTION 4 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10%. 6,000 5,000 Machine B 30000 Machine C 6,000 5,000 10000 4,000 1,000 Machine C 11779 4,000 1,000

EMIS 2360 – EXal Problem 2 A candy company with a MARR of 15% per year must purchase a new candy bar wrapping machine. Cost data for the two machines under consideration are listed below. Which machine should the company purchase? Machine A Machine B $65,000 $12,000 $25,000 6 years Initial Cost $40,000 Annual Operating Cost Salvage Value Life $10,000 $12,000 3 years

2 Costs and expenses Project 5 7 initial investment cost 528.000 years additional major maintenance in year 3 additional major annual operation and maintenance expense annual labor costs 21.000 maintenance in year Salvage value Annual income ($) A Economic life Cost of capital 75.000 130.000 $20.000 250.000 375.000 235.000 of D 9.500 11.000 27.000 B 85.000 90.000 180.000 320.000 380.000 270.000 125.000 160.000 6 15%. Project B 785.000 7.850 18.000 8.000 40.000 8 15. TOMOS Annual Equivalent Net Income which on using method implementation determine the need.

Q3 A reactor of special design un the major item of equipment in a small chemical plant. The initial cost of a Completely installed reactor is $ 60000 to the salvage value of the end of the useful life is estimated to be $ 10000. The total annual expenses for the plant are $100000. Excluding depreciation costs for the reactor. How many years of useful life should de estimated for the reactor if 12% of the total annual expenses for the Plant are due to the cost for reactor depreciation?

Q3 A reactor of special design un the major item of equipment in a small chemical plant. The initial cost of a Completely installed reactor is $ 60000 to the salvage value of the end of the useful life is estimated to be $ 10000. The total annual expenses for the plant are $100000. Excluding depreciation costs for the reactor. How many years of useful life should de estimated for the reactor if 12% of the total annual expenses for the Plant are due to the cost for reactor depreciation? 1 Add File Page 2 of 2 Back Submit ever submit passwords through Google Forms.

( 1 contractor want to invest his money in on of project A or B if you know that the interest rate is 10%, choose the best alternative A or B using net present worth method? A 120 000 CU 15 000 CU/YEAR 10 000 CU/YEAR 12 000 CU 12 YEARS 3000 CU Initial investment Annual revenue Annual expense Salvage value Project life Cost of machines replaced every 3 حلقه میشو الباب diq Naama years B 135 000 CU 17 000 CU/YEAR 11 000 CU/YEAR 20 000 CU/YEAR 6 YEARS 3500 CU

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23 Not yet anwered Points out of 3.00 Pgquestion A contractor has purchased a wheel loader for $115,000 and plans to use it 2,000 hours per year. The cost of one set of tires is $25,000. At this usage rate, the contractor anticipates disposing of the loader after using it for 10 years and realizing a salvage value of $35,000. The flywheel horsepower rating of the loader's diesel engine is 105 horsepower. The interest rate is 10%. The loader operator will earn $34.00 per hour including fringe benefits, and diesel fuel costs $1.20 per gallon. How much is the contractor's hourly ownership cost for the loader if using time value of money analysis? Select one: O a. $8.27/hr Ob. $9.37/hr Oc $7.34/hr O d. $6.23/hr

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Engineering economy

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