Key 6 (1)

Name V‘E\* Animal Science 320 Fall 2022 Problem Set #6 50 points Fixed Ingredient Formulations You have been formulating diets to date using 2 ingredients. Most diets include more than 2 ingredients, In some cases, we might be adding ingredients that do not contribute the nutrient of interest (the nutrient we are formulating toward — our target) and is some cases, they do. For example, if I have formulated to protein and we need to leave space for 5% for a vitamin premix, the premix is not providing any protein and we simply need to “hold space” for the 5%. g 4’ 1. Watch the tutorial labeled: Fixed Ingredient Formulation 1 (for either Pearson Square or Algebra) (4 and solve the following using either method (Algebra or Pearson Squarc). This problem will be worked in lab. Formulate a diet to 15% crude protein using corn (8% CP) and SBM (45% CP) and saving 8% space for ingredients that need to be included but do not contain any protein (such as a vitamin/mineral premix). Therefore, our fixed ingredients are 10% and unfixed ingredients (com + SBM) are 92% of the diet to I total 100% of ingredients. F4+C4%z=100 Ca5: ‘5 Fived = 8% urfixed = Q2% Cro=92 N1s/.92 = Ib.> €=93-5 2y ¢ @”"’“"“'* (az-s).c8) ¥ 5(45)= 1S _ o5 l3-8=_8.% 1.3 -,085+ M55 = \S >F s =2y | 283%/3% x Q2= 21.4% coen $=20.L % BM " 83/3% x.92 : *D.(% SPM C=7.4% Corn 8% fixed Fixed = 8% 5 p*\ . 2. Formulate a diet to 15% starch using oats (45% starch) and soybean meal (6% starch) while saving 15% space in the diet for fat and vitamin/mineral premixes that do not contain any starch. e Gied = 15% Lnfixed = BS% 5x 0y 57 00 %/, 5% 13.lo 0415 =85 1. 18%/,85< 14. ©0=89 -9 2_‘4'5 m M-le=IlLL & | 45 - 3.7 274 Oy S B | ; i (ee-spu) s sl S 9 3_%\,ulsfl)x 85 = 253% eald “-15"f5§;5'°“15_'2,,31 27.4/#)x . 85 =59.1% SBM 425q.3% “BM 157 fxed 0a35= 35 29, | e

14 3. Formulate a grain supplement that contains 14% crude protein. Assume the diet contains | g, ®y premix-thateentains-5%protem. You will use a combination of oats (9% crude protein) ang myb; meal (45% crude protein) to formulate the diet. X 10% fixed qo% 0% 045 = 100 : 0+5 =90 1. 14/.90: 6.6 2 9 mqs-/s.b: 294 0 =90-5 4!l =="K.p-9q = /;‘)14 i G4 T 4 us) =14 3.29.4/36 x 907 74% (735 (a0 %XMZ: ‘\’(%2_“ - o 8.l - 045« , 2 b.lte /36 x.90 = (/@,% s6m ek 4. BEEF S= o4, 0=73.l0% lo ?& ‘An 800 Lb medium frame finishing heifer is consuming 25 Lb As-Fed a diet with the following characteristics (Abbreviations: DMI = dry matter intake): * 85% DM ® 0.0 Meal per pound NEm (DM basis) ® 0.70 Mcal per pound NEg (DM basis) [ e Body Weight, Lb 600 700 800 a5 N NEm Requirement (Mcal/day) % 5.16 5.80 6.41 Expected Daily NEg Requirement (Mcal/day) gain, Lb 1.0 1.90 213 235 2.0 4.12 4.63 5.11 2.4 5.05 5.67 6.27 28 6.00 7.74 745 3.0 6.49 7.39 8.11 32 6.97 7.83 8.65 34 7.46 8.38 9.89