Animal Science 320-18

al Science 320 Fall 2023 Problem Set 1 50 points EXERCISE L Youw < many conversions throughout the semester. Here are the most common ones we will use with the factors that vou can utilize throughout the semester: 1 pound = 454 grams 1 ounce = 28 grams 1 pound = 0.45 kilograms 1 kg = 2.2 pounds 1,000 gram = 1 kilogram 1,000 milligram = 1 gram 1 ton = 2,000 pounds 1 bushel corn = 56 pounds Read Chapter 1 of the E Text and complete the Chapter 1 Pre-Lab Assessment for 4 points (1/2 point per question). EXERCISE 2 — CRITICAL SKILL: Percent. Decimal & Algebra Review 1. Ingredients in diets are typically calculated as a % in the diet. A percent (%) is always out of 100 of something. Therefore. 20 out of 100 = 20% and that could be 20 pounds, 20 grams, 20 crackers, 20 candies etc. As a basic rule “part/whole x 100 = %" For example: if we have 10 out of a total of 300 crackers, the math is completed as (10/300) x 100 =3.3% 20 Lbcom out of 100 Lb=__ L0 % Zjos X /°° Biboasomofssb=_ 9.5 % 25’/45 x 100 H 30 Lb barley out 450 Lb= ; % 3”/450 x (D0 10 tons alfalfa hay out of 20 tons = _ S % 19/, x 100 2. Diet formulations are represented as weights (or mass) and also as concentrations (typically %) and can be sed either way if you know the formulation. Take for example the following formulation represented and note the 2 columns on the right are the exact same formulation using 100 pounds and 100 Kg: [ You could also say. You could also say this: | |25 pounds com 25 Kg com | 20 pounds distillers grains 20 Ky distillers grains 130 pounds soybean meal 30 Ky soybean meal | | 20 pounds alfalfa hay 20 Ky alfalfa h | |5 pounds vitamin/mineral premix 5 Ky vi al premix Total - 100 pounds Total 100 Ky

I£1 wish to make 10.000 pounds (#ions) of the diet represented in the table above, how many pounds of cach ingredient do I need: = 286D Poundscom /0,000 X .25 - 2060 pounds distillers grains )0, 600 X%+ 2.0 2000 Pounds ofalfalfatay /0, co0x . 22,20 = 300D Poundsofsoybeanmeal " x 2O = o me 500 pounds of vitamin/mineral premix sp , p00< . OS = /10 600)) 4 / 3. Now assume you have the following diet in units of mass (kg in this case). Convert the diet to percent units. 200 kilograms corn —_ w kilograms soybean meal (SBM) Jotol = ROSO K p 300 kilograms of oats 150 kilograms of soybean hulls 50 kilograms of vitamin/mineral premix (VMP) S8.5 %com /Z°°/zoso x lo0 [Z. ] %sBM ZSD/ZDSD x (00 9.l %oas 3045/2050 X o0 7.3 % soybean hulls ’So/zoso %100 2.4 o o YME ;V,’bso Xxr00 = (99.9) 100% (diet formulations should always total 100% 4. We will also use algebra when formulating diets. These types of algebra problems should be review from previous courses and we will be using this level of algebra throughout the course. If needed, use 1 decimal == place in g 4 a6x+3=7x—1(0lveforx) [y 071;/ b.x+y=100 (x = 10; solve for y) /gr@ o0 C.2x+2(x+5)= 16x-7 4’}(/—/0: /[;X % d. 100 —x=25 z =/ 0-x=2 1#212x [x= 1Y) | 180