IM 506 Estimating Projects Exercises

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Southeast Missouri State University *

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506

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Industrial Engineering

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Dec 6, 2023

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docx

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1. Below is a project WBS with cost apportioned by percent. If the total project cost is estimated to be $800,000, what are the estimated costs for the following deliverables? A) Design ($800,000 X 0.4) = $320,000 B) Programing ($800,000 X 0.22) = $176,000 C) In the house testing ($800,000 X 0.4) = $320,000

2. Assume you are the project manager for the Tidal 2 software project. You have been asked to calculate the expected cost for the project. Your company’s database indicates that developers can handle 8 function points each person-month and that the cost per developer at your firm is $5,000 per month. You and your team of developers have come up with the following requirements: Elements Count Complexity Inputs 10 Low Output 4 Low Inquiries 4 High Files 28 Average Interfaces 18 High Complexity Weighting Element Count Low Average High Total Inputs 10 10 X 2 20 Outputs 4 4 X 3 12 Inquiries 4 4 X 6 24 Files 28 28 X 8 224 Interfaces 18 18 X 15 270 Total 550

A) Estimated total number of function points? = (10 x 2) + (4 x 3) + (4 x 6) + (28 x 8) + (18 x 15) = 20 + 12 + 24 + 224 + 270 = 550 B) Duration = Total Function Points / (Number of Developers x Function Points per Person-Month) = 550 / (5 x 8) = 550 / 40 = 13.75 C) Estimated cost? Estimated Cost = Number of Developers x Cost per Developer per Month x Duration of Project in Months = 5 * 5,000 * 13.75 = $343,75 3. Omega 2 Project. The cost of the project is $7,000. Using the “complexity weighting” scheme and the function point complexity weighted table shown below, estimate the total function point count. Assume historical data suggest five function points equal one person month and six people have been assigned to work on the project. Elements Count Complexity Inputs 15 Low Output 20 Average Inquiries 10 Average Files 30 Average Interfaces 50 High

A) Estimated number of persons = Total function points / 5 = 1,180 / 5 = 236 B) Estimated duration, if 6 people are available. = 1,180 / 6 = 196.6 If 20 people are available = 1,180 / 20 = 59 Complexity Weighting Element Count Low Average High Total Inputs 15 15 X 2 30 Outputs 20 20 X 6 120 Inquiries 10 10 X 4 40 Files 30 30 X 8 240 Interfaces 50 50 X 15 750 Total 1,180

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