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Lone Star College System, Woodlands *

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Course

310

Subject

Marketing

Date

Jan 9, 2024

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jpeg

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1

Uploaded by DoctorGazelle1431

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21 Week 4 Test Week 4 Test il “““‘“{g m‘u“““‘“ M‘””H ! | 1:/.:1 pomt Ew The average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a ‘_ | 4]! standard deviation of 0.38 ounces. If a random sample of eighty 16-ounce beverage cans are selected, what f“‘f | is the probability that mean of this sample is less than 16 1 ounces of beverage? Answer: (round to 4 i decimal places) 0.0298 v tuestion 17 f]ff | =NORM.DIST(l6.1,16.18,0.042485,TRUE); ?:Eéuestion 42 1/ 1 point The average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 ounces. If a random sample of sixty-five 16-ounce beverage cans are selected, what is the probability that the mean of this sample is !ess than 16.1 dunces of beverage? Answer: (round to 4 decimal places) 0.0534 v i W Hide question 18 feedback New SD = .4/SQRT(65) = 0.049614 P(x < 16.1), in Excel =NORM.DIST(16.1,16.18,0.049614, TRUE) A | pomt
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