Midterm2Practice-SP22-KEY
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School
North Carolina State University *
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Course
312
Subject
Mathematics
Date
Feb 20, 2024
Type
Pages
12
Uploaded by bzwilson1000.
ST 312: Midterm 2 Review Problems
Part I: Multiple Choice, True/False Questions 1.
When is the Satterthwaite approximation for the degrees of freedom necessary? a.
When the population variances are unknown b.
When the population variances are unequal c.
When the population variances are equal d.
When the data are paired e.
When the sample variances are unequal 2.
A pooled variance estimator is used when…
a.
The data is paired b.
Calculating the sample size c.
The null hypothesis is true d.
The variances of two populations are assumed equal e.
The variances of two populations are unequal 3.
A pooled proportion estimator is used when…
a.
The sample proportions are unknown b.
Finding the minimum sample size c.
Conducting a hypothesis test for ?
1
−
?
2
d.
Constructing a confidence interval for ?
1
− ?
2
e.
All of the above 4.
The Normal distribution can be used as the sampling distribution under the null hypothesis for a test concerning ?
1
− ?
2
if…
a.
The sample sizes (
𝑛
1
, 𝑛
2
) are larger than 30 b.
The distributions of 𝑋
1
and 𝑋
2
are binomial c.
Either 𝑛
1
?
1
, 𝑛
1
?
1
≥ 10
or 𝑛
2
?
2
, 𝑛
2
?
2
≥ 10
d.
Both 𝑛
1
?
1
,
𝑛
1
?
1
≥ 10
and 𝑛
2
?
2
,
𝑛
2
?
2
≥ 10
5.
The Normal distribution can be used as the sampling distribution under the null hypothesis for a test concerning 𝜇
1
− 𝜇
2
if…
a.
The sample sizes (
𝑛
1
, 𝑛
2
) are larger than 30 b.
The distributions of 𝑋
1
and 𝑋
2
are Normal c.
The variances (
𝜎
1
, 𝜎
2
) are known d.
Both a
and c
above e.
Either a
or b
, and c
above
6.
A Chi-
Square statistic can be used to test for independence when…
a.
The sample size is at least 30 b.
The observed cell counts are all 5 or greater c.
The expected cell counts are all 5 or greater d.
The test statistic is larger than the critical value 7.
A hypothesis test to determine if the mean of population A is larger than the mean of population B finds a test statistic of 1.85. Interpret this value. a.
The difference between 𝜇
?
and 𝜇
?
is 1.85. b.
The difference between 𝑥̅
?
and 𝑥̅
?
is 1.85. c.
If the population means were equal, the difference between 𝑥̅
?
and 𝑥̅
?
lies 1.85 standard deviations above 0. d.
If the population means are both 0, the difference between 𝑥̅
?
and 𝑥̅
?
lies 1.85 standard deviations above 0. 8.
A hypothesis test to determine if the mean difference of treatment A and treatment B is greater than 0 results in a p-value of 0.04. Interpret this value. a.
The probability that the null hypothesis is true is 0.04. b.
The probability that the mean difference is greater than 0 is 0.04. c.
The probability of observing a mean difference equal to or greater than the sample mean difference is equal to 0.04. d.
The probability of observing a mean difference equal to or greater than the sample mean difference, assuming the true mean difference is 0, is equal to 0.04. e.
The probability of observing a mean difference equal to or greater than 0, assuming the true mean difference is greater than or equal to than the sample mean difference, is equal to 0.04. 9.
The t
critical value for a 95% confidence interval estimation with 24 degrees of freedom is a.
1.71 b.
2.064 c.
2.492 d.
2.069 10.
The z
critical value for a 99% confidence interval estimation is a.
1.645 b.
1.96 c.
2.33 d.
2.58
11.
The rejection region for a Chi-square test of independence where 𝛼 = 0.05 and the two-way table consists of 4 rows and 3 columns is a.
?? = {𝜒
2∗
< 11.07}
b.
??
=
{
𝜒
2
∗
>
12
.59
}
c.
?? = {𝜒
2∗
< 12.59}
d.
?? = {𝜒
2∗
> 14.07}
e.
?? = {𝜒
2∗
> 21.03}
f.
?? = {𝜒
2∗
< 21.03}
12.
In a two-tailed hypothesis test the test statistic z* is determined to be -2.5. The p-value for this test is a.
-1.25 b.
0.4938 c.
0.0062 d.
0.0124 13.
In a left-tailed hypothesis test, the test statistic z* is determined to be -2. The p-value for this test is a.
0.4772 b.
0.0228 c.
0.0056 d.
0.0238 14.
In a left-tailed hypothesis test, the test statistic t* is determined to be -2 with df = 9. The p-value for this test is a.
0.038 b.
0.962 c.
0.000 d.
1.0 15.
A test for paired differences uses which sampling distribution? a.
A standard normal b.
A t
distribution with df = the total number of observations c.
A t
distribution with df = the total number of observations - 1 d.
A t
distribution with df = the total number of differences e.
A t
distribution with df = the total number of differences –
1
16.
The value added and subtracted from a point estimate in order to develop an interval estimate of the population parameter is known as the a.
confidence level b.
margin of error c.
confidence coefficient d.
parameter estimate e.
interval estimate f.
critical value 17.
Which value(s) are used as an estimator(s) for the proportions ?
1
and ?
2
when calculating the standard error of ?̂
1
− ?̂
2
during a hypothesis test? a.
?̂
1
b.
?̂
2
c.
Both ?̂
1
and ?̂
2
d.
?̂
18.
If a test rejects 𝐻
0
: µ
1
= µ
2
, then the confidence interval for (μ
1
–
μ
2
) having the same error rate does not contain zero. a.
True b.
False 19.
If the calculated value of the t
test statistic is negative, then there is strong evidence that the null hypothesis is false. a.
True b.
False 20.
Expected cell counts are calculated the same way in the tests for independence and goodness-
of-fit. a.
True b.
False 21.
The Chi-square goodness-of-fit test always assumes the proportions to be equal under the null hypothesis. a.
True b.
False 22.
A Chi-square test for independence returns a test statistic that is greater than the critical value. We can conclude that the variables are dependent. a.
True b.
False
23.
A study is conducted to evaluate of the improvement in aerobic fitness for 15 subjects where measurements are made at the beginning of a fitness program and at the end of it. Measurements are made such that a higher aerobic score represents a greater aerobic fitness level. Which set of hypotheses is correct for this test? Let d = ending aerobic score –
beginning aerobic score
. a.
𝐻
0
: 𝜇
𝑑
= 0
𝐻
?
: 𝜇
𝑑
≠ 0
b.
𝐻
0
: 𝜇
𝑑
≥ 0
𝐻
?
: 𝜇
𝑑
< 0
c.
𝐻
0
:
𝜇
𝑑
≤ 0
𝐻
?
:
𝜇
𝑑
> 0
d.
𝐻
0
: 𝜇
𝑑
> 0
𝐻
?
: 𝜇
𝑑
≤ 0
e.
𝐻
0
: 𝜇
𝑑
< 0
𝐻
?
: 𝜇
𝑑
≥ 0
24.
The deterioration of pipeline networks across the country is a growing concern. One rehabilitation option proposed is to thread a liner through existing pipe. Wishing to know whether fusing liner to the pipes increases tensile strength, measurements were taken for 10 unfused liners and 8 fused liners. A 95% confidence interval for 𝜇
𝑁? 𝑓𝑢𝑠𝑖??
− 𝜇
𝑓𝑢𝑠𝑖??
was found to be (−488, 38)
. We can conclude: a.
There is no significant difference in tensile strength between fused and unfused liners because 0 is in the interval. b.
There is a significant difference in tensile strength between fused and unfused liners because 0 is in the interval. c.
The null hypothesis is true. d.
There is not enough evidence to suggest mean tensile strength in fused liners is greater than unfused liners because 0 is in the interval. e.
There is enough evidence to suggest mean tensile strength in fused liners is greater than unfused liners because 0 is in the interval. 25.
We are interested to know if a student’s major area (humanities, scien
ces, business) affects whether they work a job (no job, part-time job, full-
time job). To test this idea, we should use…
a.
Two-sample hypothesis test for 𝜇
1
− 𝜇
2
b.
Two-sample hypothesis test for ?
1
− ?
2
c.
Chi-Square Test for Independence d.
Chi-Square Goodness-of-Fit test
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