Lab 3
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School
University of California, San Diego *
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Course
11
Subject
Mathematics
Date
Feb 20, 2024
Type
docx
Pages
7
Uploaded by MegaThunder11517
Carina Rocha A17544340
Math 11
Section B04
April 10, 2023
The regression equation is
BMR = 75.97 + 0.2822 Mass
Model Summary
S
R-sq
R-sq(adj)
300.522
84.87%
84.85%
Analysis of Variance
Source
DF
SS
MS
F
P
Regression
1
303570137
303570137
3361.29
0.000
Error
599
54097824
90314
Total
600
357667961
1.
The equation for the regression line is 75.97 + 0.2822 (mass of animal) = basal metabolic
rate. My scatterplot shown above displays the basal metabolic rate compared to body mass. 2.
The regression line for the Cape Porcupine is 75.97 + 0.2822 (11300) = 3264.83. In this case, the regression equation predicts the correlation between the explanatory variable mass in grams and the responsive variable of BMR in millimeters per hour. Since the
mass is 11300 grams the predicted BMR is about 3000. The San Diego Pocket Mouse has
a regression line equation of 75.97 + 0.2822 (19.6) = 81.501. The predicted BMR for the Pokect Mouse is less than 1000. My predictions matched up with the observations from the linear regression. 3.
The residual plot is not appropriate for predicting the basal metabolic rate from Mass because its distribution of residuals is cone-shaped. As shown in the residual plot above the variance for residuals increases as the mass increases therefore the plot effectively depicts the data for small masses but not for large masses since the residuals increase from the horizontal line.
The regression equation is
LNBMR = 1.474 + 0.6736 LNmass
Model Summary
S
R-sq
R-sq(adj)
0.369134
93.04
%
93.03%
4.
The histograms with the original variables have a heavy right skewness, resulting in outliers. While the transformed variables have a bimodal distribution. Therefore the transformed variables have a reduced skew compared to the original variables.
5.
The regression equation is ln(BMR) = 1.474 + 0.6736 ln(mass)
6.
The b value in my regression equation is 0.6736 which is closer to ⅔ supporting my results. 7.
In the transformed plots, the residual plot is random and perfectly depicts the data. The randomness means the linear regression has found the best-suited regression line for the data. In the original scatter plot the data only works best for smaller mass but not larger mass as it is harder to estimate since there is no correlation between larger variations. Unlike the transformed scatter plot, the values have a clear correlation near the regression
line. As the explanatory variable increases (LN mass)increases so does the responsive variable (LN of BMR), this data is best suited for linear regression since there is a strong correlation between mass and BMR. 8.
My predicted equation is BMR = c*(Mass)^b, for the San Diego Pocket Mouse which is BMR =4.36(19.6)^(0.6736). My product was 32.355. For the Cape Porcupine, BMR = 4.36(11300)^(0.6736). My product for the porcupine was 2342.28. Yes, these predictions
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