Practice Quiz 13_ Attempt review
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School
Thompson Rivers University *
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Course
1901
Subject
Mathematics
Date
Apr 3, 2024
Type
Pages
9
Uploaded by CaptainArt11246
Started on
Tuesday, 1 August 2023, 3:27 PM
State
Finished
Completed on
Tuesday, 1 August 2023, 3:56 PM
Time taken
28 mins 42 secs
Question 1
Correct
Mark 1.00 out of 1.00
A prism with parallelogram bases has
faces (including the base),
edges, and
vertices.
6
12
8
Your answer is correct.
The correct answer is:
A prism with parallelogram bases has [6] faces (including the base), [12] edges, and [8] vertices.
Question 2
Correct
Mark 1.00 out of 1.00
Match the surface area formulas to the objects. Formula notation: l
is length; w
is width; h
is height; B
is base area; p
is perimeter; r
is
radius; s
is slant height.
Rectangular box
Prism
Cylinder
Cone
Pyramid
Your answer is correct.
The correct answer is: → Rectangular box, → Prism, → Cylinder, → Cone, B
+
1
2
ps
→ Pyramid
Question 3
Partially correct
Mark 0.60 out of 1.00
Match the volume formulas to the objects. Formula notation: l
is length; w
is width; h
is height; B
is base area; r
is radius.
\(lwh)\)
\(Bh\)
\(\pi {r^2}h\)
\(\frac{1}{3}\pi {r^2}h\)
\(\frac{1}{3}Bh\)
Prism
Rectangular box
Cylinder
Cone
Pyramid
Your answer is partially correct.
You have correctly selected 3.
The correct answer is: \(lwh)\)
→ Rectangular box, \(Bh\)
→ Prism, \(\pi {r^2}h\)
→ Cylinder, \(\frac{1}{3}\pi {r^2}h\)
→ Cone, \(\frac{1}{3}Bh\)
→ Pyramid
Question 4
Incorrect
Mark 0.00 out of 1.00
Imagine an Egyptian right pyramid with a square base. Suppose the sides of the square base are 80 metres long and the tallest
point in the centre of the pyramid is 80 metres above ground.
Calculate the total surface area of the pyramid (not including the base) and the volume of the pyramid. Surface area =
25000
m
, volume =
17070
m
. (Round your answers to the nearest ten; do not include any words or calculations.)
2
3
The figure below shows how to find the area of one of the lateral faces of the pyramid. We need the slant height, s
, in order to find the
area of a lateral face.
Using the Pythagorean theorem we get \(s = \sqrt {{{80}^2} + {{40}^2}} = \sqrt {8000} \) m.
So, the area of one face is \(\frac{1}{2} \times 80 \times \sqrt {8000} = 40 \times \sqrt {8000} \) m
.
Thus, the surface area (not including the base) is \(4 \times 40 \times \sqrt {8000} = 160 \times \sqrt {8000} = 14,310\) m
.
Volume \( = \frac{1}{3} \times {80^2} \times 80 = 170,670\) m
.
2
2
3
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