Week 4 Knowledge Check Homework Practice Questions
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American Public University *
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Course
302
Subject
Mathematics
Date
Jan 9, 2024
Type
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10
Uploaded by shanekag89
12/30/23, 12:36 AM
- MATH302 D002 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/le/enhancedSequenceViewer/148218?url=https%3A%2F%2Ff54cbe36-23a9-4505-85fe-e251f80ec34d.sequences…
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Week 4 Knowledge Check Homework Practice Questions
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Written Dec 29, 2023 11:55 PM - Dec 30, 2023 12:35 AM
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Attempt 1 of 4
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Overall Grade (Highest Attempt)
16 / 20 - 80 %
Question 1
1 / 1 point
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264.43___
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The length of a human pregnancy is normally distributed with a mean of 272 days with a
standard deviation of 9 days (Bhat & Kushtagi, 2006). How many days would a
pregnancy last for the shortest 20%? Round answer to 2 decimal places. Answer:
In Excel,
=NORM.INV(0.2,272,9)
12/30/23, 12:36 AM
- MATH302 D002 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/le/enhancedSequenceViewer/148218?url=https%3A%2F%2Ff54cbe36-23a9-4505-85fe-e251f80ec34d.sequences…
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Question 2
0 / 1 point
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0.359___
(0.0359,
.0359)
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Question 3
1 / 1 point
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53.78___
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Question 4
0 / 1 point
Which type of distribution does the graph illustrate?
Find P(Z ≥ 1.8). Round answer to 4 decimal places. Answer: In Excel,
=1-NORM.S.DIST(1.8,TRUE)
The size of fish is very important to commercial fishing. A study conducted in 2012
found the length of Atlantic cod caught in nets in Karlskrona to have a mean of 49.9 cm
and a standard deviation of 3.74 cm (Ovegard, Berndt & Lunneryd, 2012). Assume the
length of fish is normally distributed. What is the length in cm of the longest 15% of
Atlantic cod in this area? Round answer to 2 decimal places. Answer: Longest 15% is the upper 85%, 1 - .15 = .85
In Excel,
=NORM.INV(0.85,49.9,3.74)
12/30/23, 12:36 AM
- MATH302 D002 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/le/enhancedSequenceViewer/148218?url=https%3A%2F%2Ff54cbe36-23a9-4505-85fe-e251f80ec34d.sequences…
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Question 5
1 / 1 point
The manufacturer of a new compact car claims the miles per gallon (mpg) for the
gasoline consumption is mound-shaped and symmetric with a mean of 26.3 mpg and a
standard deviation of 11.2 mpg. If 30 such cars are tested, what is the probability the
average mpg achieved by these 30 cars will be greater than 28?
Answer: ___ Round your answer to 4 decimal places as necessary. For example, 0.1357
would be a legitimate entry. Make sure you include the zero before the decimal.
___
Answer: 0.2029
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Left skewed Distribution
Right Skewed Distribution
Normal Distribution
Uniform Distribution
This is a sampling distribution problem with μ = 26.3. σ
= 11.2, and sample size n = 30.
12/30/23, 12:36 AM
- MATH302 D002 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/le/enhancedSequenceViewer/148218?url=https%3A%2F%2Ff54cbe36-23a9-4505-85fe-e251f80ec34d.sequences…
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Question 6
1 / 1 point
___
0.4966___
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Question 7
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0.314___
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Question 8
1 / 1 point
The average lifetime of a certain new cell phone is three years. The manufacturer will
replace any cell phone failing within two years of the date of purchase. The lifetime of
these cell phones is known to follow an exponential distribution. The decay rate is:
New SD = 11.2/SQRT(30) = 2.044831
P(x > 28) = 1 - NORM.DIST(28, 26.3, 2.044831, TRUE) The life of an electric component has an exponential distribution with a mean of 10
years. What is the probability that a randomly selected one such component has a life
more than 7 years? Answer: (Round to 4 decimal places.) P(x > 7)
1-P(x < 7)
=1-EXPON.DIST(7,1/10,TRUE)
The commute time for people in a city has an exponential distribution with an average of
0.5 hours. What is the probability that a randomly selected person in this city will have a
commute time between 0.4 and 1 hours? Answer: (round to 3 decimal places)
P(.4 < x < 1)
P(x < 1) - P(x < .4)
In Excel,
=EXPON.DIST(1,1/0.5,TRUE)-EXPON.DIST(0.4,1/0.5,TRUE)
0.1666
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