PHHYA10S-Test-1-SOL-2023-grading
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10
Subject
Mathematics
Date
Jan 9, 2024
Type
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10
Uploaded by CommodoreIce7997
PHYA10F – TEST#1
Sample Solution
1
Instructor: Prof. Salam Tawfiq
Oct. 14, 2023
Time:
90 Minutes
Note: Write your official name as it appeared in ACRON and write your practical
group number and/or name of your TA. Falling to do so, 2 points will be deducted.
You may use a non-programmable calculator and one aid sheet.
The aid sheet must
be hand-written on a normal (8.5 by 11) page, one side is acceptable with a maximum
of 20 equations
. It should contain formulae only no definitions, graphs, explanation or
problems and will be collected at the end of the test. No other aids are allowed. This
includes neighboring students. Cell phones and other electronic devices will be
confiscated if they make noise or if you are using them.
Answer all the questions.
There are 10 multiple-choice (MC) questions and 3 short
answer questions & problems.
The multiple-choice questions are worth 3 mark each. The
short answer questions and problems are worth 10 marks each. The test is out of a total of
60 marks.
Do not remove the staple. There are a couple of blank sheets at the end for rough work;
you may carefully remove them if you wish.
You have a total of
90 Minutes
to write this test. You are advised not to
spend more
than 4 minutes
on each question on part-A of the test and
not more than 14 minutes
on
each question of part-B.
Do not open this booklet before the Test begins.
Part-A (MC)
/30
Part-B
Q1
/10
Q2
/10
Q3
/10
Total
Out of 60
GOOD LUCK
PHYA10F – TEST#1
Sample Solution
2
Fill in the table below with your best choice
for part A
Q1
Q2
Q3
Q4
Q5
Q6
Q7
Q8
C
C
E
B
A
A
C
C
Q9
Q10
A
B
Provide your solution for part-B in the space provided.
PHYA10F – TEST#1
Sample Solution
3
Part-B: Problem Solving
Q1:
(10 points total)
A.
i.
What is the rocket's maximum altitude?
The maximum altitude is
In the acceleration phase:
In the coasting phase,
The maximum altitude is 54.8 km
ii.
How long is the rocket in the air before hitting the ground?
Then
is found by considering the time needed to fall 54,800 m:
iii.
Draw a clear velocity-time graph for the rocket from liftoff until it hits the
ground. On the graph, identify the time when the rocket runs out of fuel, max
altitude & hitting the ground.
a
=
−
g
.
y
2
.
y
1
=
y
0
+
v
0
(
t
1
−
t
0
)
+
1
2
a
(
t
1
−
t
0
)
2
=
1
2
at
1
2
=
1
2
(30 m/s
2
)(30 s)
2
=
13,500 m
v
1
=
v
0
+
a
(
t
1
−
t
0
)
=
at
1
=
(30 m/s
2
)(30 s)
=
900 m/s
v
2
2
=
0
=
v
1
2
−
2
g
(
y
2
−
y
1
)
⇒
y
2
=
y
1
+
v
1
2
2
g
=
13,500 m
+
(900 m/s)
2
2(9.8 m/s
2
)
=
54,800 m
=
54.8 km
(
≈
33 miles).
v
2
=
0 m/s
=
v
1
−
g
(
t
2
−
t
1
)
⇒
t
2
=
t
1
+
v
1
g
=
122 s
t
3
y
3
=
0 m
=
y
2
+
v
2
(
t
3
−
t
2
)
−
1
2
g
(
t
3
−
t
2
)
2
=
y
2
−
1
2
g
(
t
3
−
t
2
)
2
⇒
t
3
=
t
2
+
2
y
2
g
=
228 s
2 points
2 points
2 points
PHYA10F – TEST#1
Sample Solution
4
B.
The displacement (or angular position) is the area under the angular velocity graph (see
Figure to right), but we need calculus to do this for a nonlinear graph.
2 points
2 points
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