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A solid uniform disk of radius R = 0.2 m and mass M = (.34 kg is free to rotate about an axis through its center. String is wound around the rim and pulled with a force, F, causing an angular acceleration of a=1.2rad/ s%. Assume the disk starts from rest when the force F starts pulling att = 0. Center Through what total angle & will the disk rotate in 8 seconds? (a) ¢ = 4.80 rad (b) 87 = 76.80 rad (c) O = 38.40 rad v 100% What is the magnitude of the force, F? (a) F = 0.041N (b) F = 2.040N (c) F = 0.008 N v 100% Which expression is correct for the moment of inertia of the disk about an axis parallel to the axis through the center and located at its rim, as shown in the figure? Parallel (@) Lparatter = (2.5) M R? (b) Iparanter = (1.5) M R? () Lparaer = (0.5)MR* 3 (d) Lparattet = MR? (@) Iparanter = (4.5) M R? This question is complete and cannot be answered again. (c) 07 = 38.40 rad (@) F = 0.041N (b) Iparallel = (IS)MR2